A total positive charge of 12.00 mC is evenly distributed on a straight thin rod of length 6.00 cm.

Un alumno menciona que al abrir la ventana de su casa sintió cómo el frío ingresaba a su cuerpo. Menciona cuál es la verdadera r

stepan [7]

Answer:

My believe the answer is

A.) or B.)

Explanation:

Here is why I think A is the answer.

If we use the process of elimination, it would look like this,

a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.

This makes sense because we all know in winter the weather is very cold and freezing.

b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.

I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.

c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.

This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.

d) Porque la temperatura del aire es igual a la temperatura del cuerpo.

This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.

<h2>Well, have a nice rest of the day!</h2><h3>ba baiii!</h3>

3 0

3 years ago

Considerando que você comece a caminhar em velocidade constante, inicialmente a 350 m de um ponto referencial escolhido. Você ca

ExtremeBDS [4]

Answer:

a. S(t)=350−1t

Explanation:

To determine the equation of motion you take into account the general form of motion with constant velocity:

$S(t)=S_o+vt$ ( 1 )

So is the initial position from a specific reference frame. In this case is 350 m.

v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.

You replace the values of So and v in the equation ( 1 ) and you obtain:

$S(t)=350-(1m/s)t$

Hence, the answer is:

a. S(t)=350−1t

- - - - - - - - - - - - - - - - - - - - -

Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:

(1)

Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.

v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.

Você substitui os valores de So ev na equação (1) e obtém:

Portanto, a resposta é:

uma. S (t) = 350-1t, movimento retrógrado

4 0

3 years ago

How long does it take anya to cover the distance of 5.00 miles ?

sammy [17]

Here is the full information about the question. Ilya and Anya each can run at a speed of 8.50mph and walk at a speed of 3.50 mph . They set off together on a route of length 5.00 miles . Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.
the calculation would be:

t = d / s 
t = 2.5 (half of the total distance) / 8.5 (speed of running) 
This is .294 hours which is about 1058s... 

for the walking part... 

t = d / s 
t = 2.5 / 3.5 
t = 5/7hours = 2571 s.

5 0

3 years ago

A 5.75 mm high firefly sits on the axis of, and 11.3 cm in front of, the thin lens A, whose focal length is 5.77 cm . Behind len

weeeeeb [17]

Answer

given,

focal length of lens A = 5.77 cm

focal length of lens B= 27.9 cm

flies distance from mirror = 11.3 m

now,

Using lens formula

$\dfrac{1}{f} = \dfrac{1}{p} + \dfrac{1}{q}$