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finlep [7]
3 years ago
11

A total positive charge of 12.00 mC is evenly distributed on a straight thin rod of length 6.00 cm.

Physics
1 answer:
Gala2k [10]3 years ago
3 0
It’s not in English can you change it please
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The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g o
satela [25.4K]

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

4 0
3 years ago
Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wave
Alisiya [41]

Answer:

similar wave amplitudes

Explanation:

When two waves travelling in the same medium have similar wave amplitudes they are less likely to interfere with each other destructively or constructively because the interference between waves occur when the amplitudes of the waves arrive a position in the medium in opposite directions hence they add up( superposition) or cancel each other out.

Hence if the waves have similar wave amplitudes the interference between the waves will be limited.

8 0
4 years ago
Read 2 more answers
If you measured the mass of a book to be 2.5 kilograms how many grams is that
vodomira [7]

Answer:

2.5 kilograms = 2500 grams

5 0
3 years ago
Which best describes the current atomic model?
Lorico [155]
<span>A: It is not an exact representation of the atom, but is close enough to be very useful.

Hope this helps!</span>
3 0
3 years ago
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A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of
Leni [432]

Answer:

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

Lc=188.4 m

The magnetic filed given as

B=\dfrac{\mu_oNI}{L}

I=\dfrac{BL}{\mu_oN}

Now by putting the values

I=\dfrac{0.0064\times 0.6}{4\pi \times 10^{-7}\times 600}

I=5.09 A

The resistance R given as

R=\dfrac{\rho L_c}{A}

A=\dfrac{\pi}{4}\times d^2

A=\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2

R=\dfrac{1.7\times 10^{-8} \times 188.4}{\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2}

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

5 0
3 years ago
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