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Irina-Kira [14]
3 years ago
11

Why are clockwise and counterclockwise referred to as “senses,” rather than directions?

Physics
2 answers:
Y_Kistochka [10]3 years ago
8 0

Clockwise and counter-clockwise is considered as a sense rather than a direction because it is only a view point where its movement of direction is always changing. Moreover, it is assumed as a tangential velocity of different points on the same body that is spinning in all directions and do not describe the motion of an object. The term can only be applied to object-observer system and not particularly for a direction.

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Jobisdone [24]3 years ago
5 0

Answer: Hello there!

Let's suppose that are directions

Suppose that the hour hand of the clock is on the 3, then the "direction" clockwise points down, and the direction "counterclockwise" points up.

Now if the hour hand is in the 12, the clockwise "direction" points to the right, and the counterclockwise points left.

Then you can see that the direction changes depending on where are we looking, this is the reason for them to be called "senses", because in this way you don't need to, for example, use the position of the object which movement is being described.

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1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de apl
Rudik [331]

Answer:

τ= F r     into the blade

Explanation:

The moment of a force is defined by

         τ = F x r

where the bold indicates vectors

Let us write in the expression in magnitude

         τ = F r sin θ

in our case the force is tangent to the wheel therefore the angle between F and the radius is 90º, and the sin 90 = 1

       τ= F r

The direction of τ can be used by the rule of the right hand, the fingers curve in the direction of the torque when advancing from the force to the radius and the thumb points in the direction of the torque.

In this case, for a clockwise rotation, the fingers are curved in the direction and the thumb points into the blade, this is the direction of the τ.

TRASLATE

El momento de una fura es definido por

         τ = F x r

donde la negrillas indican vectores

Escribamos en ta expresión en magnitud

          τ = F r sin θ

en nuestro caso la fuerza es tangente a la rueda por lo tanto el angulo entre F y el radios es 90º, y el sin 90=1

        τ = F r

la dirección de tau la podemos  usar la regla de la mano derecha, los dedos curva en la dirección del torque al avanzar dese la fuerza al radio y el pulgar apunta en la dirección del torque.

En este caso para un giro en sentido horario los dedos se curvan ente sentido y el pulgar apunta hacia dentro de lla hoja, esta es la dirección del troque

5 0
4 years ago
Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of 8.0 mm. A tensile force of 1000 N produc
Dimas [21]

Answer:

1.7 × 10^11 Pa

Explanation:

Please see the attachments below

3 0
3 years ago
What is the first step of the STOP procedure for assessing acute sports injuries?
Troyanec [42]
The first step of the STOP procedure is S, which stands for "stop." This indicates that you should stop what you're doing to place your full attention on the situation at hand. This will allow you to stay focused on what's specifically happened to an athlete. 
3 0
3 years ago
Read 2 more answers
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

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We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

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Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
How does the force on the rifle compare with the force on the bullet, and why?
I am Lyosha [343]
They are equal and opposite (action and reaction)
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