speed of the car is given on the road
![v = 22 m/s](https://tex.z-dn.net/?f=v%20%3D%2022%20m%2Fs)
reaction time is given as
![t = 0.50 s](https://tex.z-dn.net/?f=t%20%3D%200.50%20s)
now we can find the distance that it will move during this reaction time
![d_1 = 22* 0.50 = 11 m](https://tex.z-dn.net/?f=d_1%20%3D%2022%2A%200.50%20%3D%2011%20m)
now the deceleration of the car is 10 m/s^2
so the distance that it will move before stop is given by
![v_f^2 - v_i^2 = 2 a d](https://tex.z-dn.net/?f=v_f%5E2%20-%20v_i%5E2%20%3D%202%20a%20d)
![0^2 - 22^2 = 2*(-10)*d](https://tex.z-dn.net/?f=0%5E2%20-%2022%5E2%20%3D%202%2A%28-10%29%2Ad)
![d = 24.2 m](https://tex.z-dn.net/?f=d%20%3D%2024.2%20m)
so the total distance that it require to stop is given as
![d = 24.2 + 11 = 35.2 m](https://tex.z-dn.net/?f=d%20%3D%2024.2%20%2B%2011%20%3D%2035.2%20m)
while the deer is standing at distance 38 m
so the car will stop 2.8 m before the position of deer
Answer:
The value is ![E = 1.35 *10^{14} \ J](https://tex.z-dn.net/?f=E%20%3D%20%201.35%20%2A10%5E%7B14%7D%20%5C%20J)
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is ![m = 1 \ g = 0.001 \ kg](https://tex.z-dn.net/?f=m%20%20%3D%20%201%20%5C%20%20g%20%20%3D%200.001%20%5C%20%20kg)
The mass of matter converted to energy on second test ![m_1 = 1.5 \ g = 1.5 *10^{-3} \ kg](https://tex.z-dn.net/?f=m_1%20%3D%20%201.5%20%5C%20%20g%20%3D%201.5%20%2A10%5E%7B-3%7D%20%5C%20kg)
Generally the amount of energy that was released by the explosion is mathematically represented as
![E = m * c^2](https://tex.z-dn.net/?f=E%20%3D%20%20m%20%2A%20c%5E2)
=> ![E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2](https://tex.z-dn.net/?f=E%20%3D%20%201.5%20%2A10%5E%7B-3%7D%20%20%2A%20%5B%203.0%20%2A10%5E%7B8%7D%5D%5E2)
=> ![E = 1.35 *10^{14} \ J](https://tex.z-dn.net/?f=E%20%3D%20%201.35%20%2A10%5E%7B14%7D%20%5C%20J)
Answer:
A super conductor is a perfect conductor that has zero resistance. It doesn't just have very low resistance and conducts electricity well, it has ZERO resistance and conducts electricity perfectly with no losses at all
A transverse wave is a wave where the particles in the medium move perpendicular (at right angles) to the direction of the source or its propagation (think of a snake slithering through grass) an example of a transverse wave could be a light wave. Light waves for instance don’t need a medium in order to propagate but transverse waves in general do need a medium.
Answer:
11760 joules
Explanation:
Given
Mass (m) = 75kg
Height (h) = 16m
Required
Determine the increment in potential energy (PE)
This is calculated as thus:
PE = mgh
Where g = 9.8m/s²
Substitute values for m, g and h.
P.E = 75 * 9.8 * 16
P.E = 11760 joules