There is no temperature change which drives heat flow, thus no heat will be released by the water.
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Heat released by the water when it freezes</h3>
The heat released by the water when it freezes is calculated as follows;
Q = mcΔФ
where;
- m is mass of water
- c is specific heat capacity of water
- ΔФ is change in temperature = Фf - Фi
Initial temperature of water, Фi = 0 °C
when water freezes, the final temperature, Фf = 0 °C
Q = 22 x 4200 x (0 - 0)
Q = 0
Since there is no temperature change which drives heat flow, thus no heat will be released by the water.
Learn more about heat flow here: brainly.com/question/14437874
While Jane is running has a kinetic energy, which is Ek = 1/2*m*v^2 where m is mass and v is velocity When she grabs a vine, she is going to change the kinetic energy to potential energy.
We know that potential energy is given by Ep = m*g*h where m is mass, g is gravity constant and h is height
So while running the kinetic energy is Ek = 1/2 * m * 5.2^2 = 13.52*m
Then all that energy is used to swing upward and gain potential energy
Ep = m*g*h = Ek = 13.52*m
m*9.8*h = 13.52*m
h = 13.52/9.8 = 1.38 meters
So Jane will swing 1.38 meters upward
Answer: W.D = 1/2mv^2
Explanation:
If an external force or a single force is acting on a body. Just like the first law of thermodynamics, the force acting on the body will cause work done on the system.
Work done = force × distance
And the work done on the body will cause the molecules of the body to experience motion and thereby producing kinetic energy.
The work done will be converted to kinetic energy.
W.D = 1/2mv^2
Answer:
C.
m
Explanation:
We are given that
Weight of board=w=10 N
Length of board=L=5 m
Tension in the string=T=3 N
Applied upward force=F=7 N
We have to find the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.
Let r be the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.
The board is uniform therefore, the center of board is the mid- point of board.
Therefore, the lever arm of weight=
Now, the torque exerted by the weight of the board
The torque exerted by applied force=
In static equilibrium
The sum of rotational forces=0
The two rotational force act in opposite direction therefore,
Substitute the values
m
Hence, option C is true.
