Solved your another question same like this with scaling to Cm this time we go with metre(m)
Scale factor
Mercury
Ven us
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
Answer:
λ = a
Explanation:
This is a diffraction exercise that is described by the expression
a sin θ = m λ
sin θ = m λ/ a
the first zero of the diffraction occurs for m = 1
sin θ = λ / a
angles are generally very small and are measured in radians
sin θ = θ = y / x
we substitute
the width of the central maximum is twice the distance to zero
w = 2y
in the exercise indicate that this width is equal to twice the distance to the screen (2x)
W = 2x
2y = 2x
we substitute
1 = λ/ a
λ = a
we see that the width of the slit is equal to the wavelength used.
Answer:
x = 333.33 [m]
Explanation:
To solve this problem we must use the following kinematics equation.
where:
Vf = final velocity = 0
Vi = initial velocity = 20 [m/s]
a = desacceleration = 0.6 [m/s^2]
x = distance [m]
Note: the final speed is zero as the body finishes its movement.
Now replacing:
0 = (20)^2 - (2*0.6*x)
1.2*x = 400
x = 333.33 [m]
They will both land at the same time.