The dependent variable is i won’t get cavities
= 6.022 × 1020
Explanation<em>;</em>
Mole of aluminium oxide (Al2O3) is
⇒ 2 x 27 + 3 x 16
Mole of aluminium oxide = 102 g
i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3
Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)
= 3.011 x 1020 molecules of Al2O3
The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)
= 2 × 3.011 × 1020
=<em> 6.022 × 1020</em>
<em>hope </em><em>it </em><em>helps</em><em>_</em>
Answer:
by using a base
Explanation:
when you put base to acid, it will form a salt and base
Answer:
6.93
Explanation:
correct me if verry wrong
Answer:
The transformation was not added. See the attached file for the structure and the answer.
Explanation:
In the first reaction it is normal nucleophilic substitution reaction on the addition of hydrobromide. Hindu second reaction first the Hydroxide Ion attacks on the tertiary carbon because it is more reactive then the anion formed is further converted into carbonyl. And on the addition of methyl iodide we get the required product.
