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frosja888 [35]
3 years ago
9

An atom of gold has a mass of 3.271 X 10-22 g. How many atoms of gold are in 5.00 g of gold? (Give your answer in scientific not

ation.) How many atoms will there be in 5.00 g of gold.
Chemistry
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

1.53 × 10²² atoms Ag

Explanation:

Step 1: Define conversions

3.271 × 10⁻²² g = 1 atom

Step 2: Use Dimensional Analysis

5.00 \hspace{3} g \hspace{3} Ag(\frac{1 \hspace{3} atom \hspace{3} Ag}{3.271(10)^{-22} \hspace{3} g \hspace{3} Ag} ) = 1.52858 × 10²² atoms Ag

Step 3: Simplify

We have 3 sig figs.

1.52858 × 10²² atoms Ag ≈ 1.53 × 10²² atoms Ag

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Ethylene glycol is used as an antifreeze in car. if 400 g of ethylene glycol is added to 4.00 kg of water, what is the molaity?
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Data:

solute: ethylene glicol => not ionization

molar mass of ethylene glicol (from internet)  = 62.07 g/mol

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m =?

ΔTf = ?

Kf = 1.86 °C/mol

Formulas:

m: number of moles of solute / kg of solvent

ΔTf = Kf*m

number of moles of solute = mass in grams / molar mass

Solution

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8 0
3 years ago
If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?
kolezko [41]

Answer:

  • <u>3.0M</u>

Explanation:

The dilution formula is:

       M_1\times V_1=M_2\times V_2

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

  • M₁ = <em>6.0M</em>
  • M₂ = unknown
  • V₁ = <em>251 mL</em>
  • V₂ = <em>500. mL</em>

         6.0M\times 251ml=M_2\times 500.ml

Clear M₂ and compute:

         M_2=6.0M\times 251ml/500.ml\approx3.0M

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