Answer:
The value of Ka 
It is a weak acid
Explanation:
From the question we are told that
The concentration of ![[HClO_2]=0.24M](https://tex.z-dn.net/?f=%5BHClO_2%5D%3D0.24M)
The concentration of ![[H^+]=0.051M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.051M)
The concentration of ![[ClO_2^-]=0.051M](https://tex.z-dn.net/?f=%5BClO_2%5E-%5D%3D0.051M)
Generally the equation for the ionic dissociation of 
is
The equilibrium constant is mathematically represented as
![= \frac{[H^+][ClO_2^-]}{[HClO_2]}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BClO_2%5E-%5D%7D%7B%5BHClO_2%5D%7D)
Substituting values since all value of concentration are at equilibrium
Since the value of is less than 1 it show that in water it dose not completely
disassociated so it an acid that is weak
Answer:
When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature
Explanation:
35.453 (chlorine) + 10.811 (boron) = 46.264
Answer:
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).
Explanation:
The reaction between an acid and a base is called neutralization, forming a salt and water.
Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.
When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:
V acid *M acid = V base *M base
where V represents the volume of solution and M the molar concentration of said solution.
In this case:
- V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
- M acid= 0.129 M
- V base= ?
- M base= 0.135 M
Replacing:
0.0137 L* 0.129 M= V base* 0.135 M
Solving:
V base=0.0131 L = 13.1 mL
<u><em>
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>
Answer:
boiling point elevation - colligative property
color - non-colligative property
freezing point depression - colligative property
vapor pressure lowering - colligative property
density - non-colligative property
Explanation:
A colligative property is a property that depends on the number of particles present in the system.
Freezing point depression, boiling point elevation and vapour pressure lowering are all colligative properties of solutions.
Colour and density do not depend on the number of particles present hence they are not colligative properties.
