Answer:
0.200 m K3PO3
Explanation:
Let us remember that the freezing point depression is obtained from the formula;
ΔTf = Kf m i
Where;
Kf = freezing point constant
m = molality
i = Van't Hoff factor
The Van't Hoff factor has to do with the number of particles in solution. Let us consider the Van't Hoff factor for each specie.
0.200 m HOCH2CH2OH - 1
0.200 m Ba(NO3)2 - 3
0.200 m K3PO3 - 4
0.200 m Ca(CIO4)2 - 3
Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.
Answer:
Approximately 
.
Explanation:
Look up the density 
of carbon tetrachloride, 
, and glycerol:
- Density of carbon tetrachloride: approximately
. - Density of glycerol: approximately
.
Let 
denote the gravitational field strength. (Typically 
near the surface of the earth.) For a column of liquid with a height of 
, if the density of the liquid is , the pressure at the bottom of the column would be:
.
The pressure at the bottom of this carbon tetrachloride column would be:
.
Rearrange the equation for :
.
Apply this equation to calculate the height of the liquid glycerol column:
.
At room temperature two atoms of nitrogen combine to form a colorless and odorless diatomic gas. it is found in gaseous state.
hope the answer is helpful.
<span> I would guess that calcium (Ca), of all the group 2 elements, is most like magnesium (Mg), because it has the most similar size (atomic and ionic radii) to Mg. </span>
