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MrRa [10]
2 years ago
13

The planet Mars has much less gravitational force than Earth. What would happen if you went to Mars?

Physics
2 answers:
katrin2010 [14]2 years ago
7 0

Answer: C. Your mass would decrease.


I think this because If the pull is less than on earth we could jump higher which means that we have a lower mass. According to my research an average person is 6.39 kg on mars.

borishaifa [10]2 years ago
4 0

The planet Mars has much less gravitational force than Earth. So if you went to Mars your weight would decrease.

Answer: Option D

<u>Explanation:</u>

Weight = mass * gravity, hence the mass of the object remains the same at earth and at Mars. When it comes to weight, it depends upon gravity of the location.

Hence at earth, due to high gravity compared to mars, the weight value will be high, whereas when it comes to mars, due to low gravity, the weight will decrease but the mass remains the same.

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3 years ago
The question is in the picture
Sedbober [7]

Answer:

e) 120m/s

Explanation:

When the ball reaches its highest point, its velocity becomes zero, meaning

v_0-gt = 0.

where v_0 is the initial velocity.

Solving for t we get

t = \dfrac{v_0}{g}

which is the time it takes the ball to reach the highest point.

Now, after the ball has reached its highest point, it turns around and falls downwards. After time t_0 since it had reached the highest point, the ball has traveled downwards and the velocity v_f it has gained is

v_f = gt_0,

and we are told that this is twice the initial velocity v_0; therefore,

v_f = 2v_0  = gt_0

which gives

t_0 = \dfrac{2v_0}{g}.

Thus, the total time taken to reach velocity 2v_0 is

t_{tot} = t+t_0 = \dfrac{v_0}{g}+\dfrac{2v_0}{g}

t_{tot} = \dfrac{3v_0}{g}.

This t_{tot}, we are told, is 36 seconds; therefore,

36= \dfrac{3v_0}{g},

and solving for v_0 we get:

v_0 = \dfrac{36g}{3}

v_0 = \dfrac{36s(10m/s^2)}{3}

\boxed{v_0 = 120m/s}

which from the options given is choice e.

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