Determine the resultant normal force across the cross section at point B. Express your answer to three significant figures and i
nclude appropriate units.
1 answer:
Complete Question
A force of F =460 lb. acts on the curved member as shown. Determine the resultant normal force across the cross section at point B. Express your answer to three significant figures and include appropriate units.(Figures Attached)
Answer:
Resultant Normal Force = 55. 02 lb.
Explanation:
In Order to find the resultant normal force we must first resolve the figure to find out the x and y components of the force across the cross-section at point B. Hence after resolving the figure we can find the resultant normal force by finding the vertical component of the force: ∑ F_y
The normal force acting at point B will be:
∑ F_y :-
N_F + 460(4/5)sin〖30〗^° - 460(3/5) sin〖60〗^° = 0
N_F + 184 - 239.02 = 0
N_F = 55. 02 lb.
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Answer:
hello below is missing piece of the complete question
minimum size = 0.3 cm
answer : 0.247 N/mm2
Explanation:
Given data :
section span : 10.9 and 13.4 cm
minimum load applied evenly to the top of span : 13 N
maximum load for each member ; 4.5 N
lets take each member to be 4.2 cm
Determine the max value of P before truss fails
Taking average value of section span ≈ 12 cm
Given minimum load distributed evenly on top of section span = 13 N
we will calculate the value of by applying this formula
= = 1.56 * 10^-5
next we will consider section ; 4.2 cm * 0.3 cm
hence Z (section modulus ) = BD^2 / 6
= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8
Finally the max value of P( stress ) before the truss fails
= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )
= 0.247 N/mm2
Answer:
The temperature T= 648.07k
Explanation:
T1=input temperature of the first heat engine =1400k
T=output temperature of the first heat engine and input temperature of the second heat engine= unknown
T3=output temperature of the second heat engine=300k
but carnot efficiency of heat engine =
where Th =temperature at which the heat enters the engine
Tl is the temperature of the environment
since both engines have the same thermal capacities <em> </em> therefore
We have now that
multiplying through by T
multiplying through by 300
-
The temperature T= 648.07k