Determine the resultant normal force across the cross section at point B. Express your answer to three significant figures and i
nclude appropriate units.
1 answer:
Complete Question
A force of F =460 lb. acts on the curved member as shown. Determine the resultant normal force across the cross section at point B. Express your answer to three significant figures and include appropriate units.(Figures Attached)
Answer:
Resultant Normal Force = 55. 02 lb.
Explanation:
In Order to find the resultant normal force we must first resolve the figure to find out the x and y components of the force across the cross-section at point B. Hence after resolving the figure we can find the resultant normal force by finding the vertical component of the force: ∑ F_y
The normal force acting at point B will be:
∑ F_y :-
N_F + 460(4/5)sin〖30〗^° - 460(3/5) sin〖60〗^° = 0
N_F + 184 - 239.02 = 0
N_F = 55. 02 lb.
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Answer:
Explanation:
attached is an uploaded picture to support the answer.
the program is written thus;
#include<iostream>
using namespace std;
// function declaration
void rShift(int&, int&, int&, int&, int&, double&);
int main()
{
// declare the variables
int a1, a2, a3, a4;
int maximum = 0;
double average = 0;
// inputting the numbers
cout << "Enter all the 4 integers seperated by space -> ";
cin >> a1 >> a2 >> a3 >> a4;
cout << endl << "Value before shift." << endl;
cout << "a1 = " << a1 << ", a2 = " << a2 << ", a3 = "
<< a3 << ", a4 = " << a4 << endl << endl;
// calling rSift()
// passing the actual parameters
rShift(a1,a2,a3,a4,maximum,average);
// printing the values
cout << "Value after shift." << endl;
cout << "a1 = " << a1 << ", a2 = " << a2 << ", a3 = "
<< a3 << ", a4 = " << a4 << endl << endl;
cout << "Maximum value is: " << maximum << endl;
cout << "Average is: " << average << endl;
}
// function to right shift the parameters circularly
// and calculate max, average of the numbers
// and return it to main using pass by reference
void rShift(int &n1, int &n2, int &n3, int &n4, int &max, double &avg)
{
// calculating the max
max = n1;
if(n2 > max)
max = n2;
if(n3 > max)
max = n3;
if(n4 > max)
max = n4;
// calculating the average
avg = (double)(n1+n2+n3+n4)/4;
// right shifting the numbers circulary
int temp = n2;
n2 = n1;
n1 = n4;
n4 = n3;
n3 = temp;
}
