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klasskru [66]
3 years ago
13

In Example 2-1, part c, the data were represented by the normal distribution function f(x)=0.178 exp(-0.100(x-451)2 Use this dis

tribution function to determine the fraction of individuals demonstrating a response in the range of 2.5 to 7.5.
Engineering
1 answer:
valkas [14]3 years ago
6 0

Answer:

P ( 2.5 < X < 7.5 ) = 0.7251

Explanation:

Given:

- The pmf for normal distribution for random variable x is given:

                                      f(x)=0.178 exp(-0.100(x-4.51)^2)

Find:

the fraction of individuals demonstrating a response in the range of 2.5 to 7.5.

Solution:

- The random variable X follows a normal distribution with mean u = 4.51, and standard deviation s.d as follows:

                               s.d = sqrt ( 1 / 0.1*2)

                               s.d = sqrt(5) =2.236067

- Hence, the normal distribution is as follows:

                               X ~ N(4.51 , 2.236)

- Compute the Z-score values of the end points 2.5 and 7.5:

              P ( (2.5 - 4.51) / 2.236 < Z < (7.5 - 4.51 ) / 2.236 )

              P ( -0.898899327 < Z < 1.337168651 )  

- Use the Z-Table for the probability required:

              P ( 2.5 < X < 7.5 ) = P ( -0.898899327 < Z < 1.337168651 ) = 0.7251            

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Answer:

Option (d) 2 min/veh

Explanation:

Data provided in the question:

Average time required = 60 seconds

Therefore,

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Now,

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⇒ \frac{1}{\mu(1-\frac{\lambda}{\mu})}

thus,

on substituting the respective values, we get

Average time spent by the vehicle = \frac{1}{60(1-\frac{30}{60})}

or

Average time spent by the vehicle = \frac{1}{60(1-0.5)}

or

Average time spent by the vehicle = \frac{1}{60(0.5)}

or

Average time spent by the vehicle = \frac{1}{30} hr/veh

or

Average time spent by the vehicle = \frac{1}{30}\times60 min/veh

[ 1 hour = 60 minutes]

thus,

Average time spent by the vehicle = 2 min/veh

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Option (d) 2 min/veh

7 0
3 years ago
A boy weighing 108-lb starts from rest at the bottom A of a 6-percent incline and increases his speed at a constant rate to 7 mi
baherus [9]

Answer:

88.18 W

Explanation:

The weight of the boy is given as 108 lb

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The slope is given as 6% , change it to degrees as

6/100 =0.06

tan⁻(0.06)= 3.43°

The boy is travelling at a constant speed up the slope = 7mi/hr

Change 7 mi/h to m/s

7*0.44704 =3.13 m/s

Formula for power P=F*v where

P=power output

F=force

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Finding force

F=m*g*sin 3.43°

F=49*9.81*sin 3.43° =28.17

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4 0
3 years ago
Your study space does not need to be quiet as long as you can ignore any noise coming from the space true or false?
Makovka662 [10]

Answer:

False

Explanation:

When you're studying, you need to make sure that you can focus properly. This means that you shouldn't be hungry or too full and that you should be well-rested, in a quiet room with good lighting and no distractions. Noise is never good when you need to memorize something. Some people can partially ignore it as long as it isn't too loud, but it will begin to bother them eventually. That's why it's better to study in a quiet room.

3 0
2 years ago
Read 2 more answers
Briefly explain how each of the following influences the tensile modulus of a semicrystalline polymer and why:(a) molecular weig
marin [14]

Answer:

(a) Increases

(b) Increases

(c) Increases

(d) Increases

(e) Decreases

Explanation:

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(b) Degree of crystallinity:

Tensile strength of the semi-crystalline polymer increases with the increase in the degree of crystallinity of the polymer.

(c) Deformation by drawing:

The deformation by drawing in the polymer results in the finely oriented chain structure of the polymer with the greater inter chain secondary bonding structure resulting in the increase in the tensile strength of the polymer.

(d) Annealing of an undeformed material:

This also results in an increase in the tensile strength of the material.

(e) Annealing of  a drawn material:

A semi crystalline material which is drawn when annealed results in the decreased tensile strength of the material.

5 0
3 years ago
A horizontal, opaque surface at a steady-state temperature of 80°C is exposed to an airflow having a free stream temperature of
lesya692 [45]

Answer:

Check the explanation

Explanation:

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7 0
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