We need to define the variables,
So,
![F_x (x) = 1-e^{-\lambda x}\\F_x (x) = 1-e^{-0.5x}](https://tex.z-dn.net/?f=F_x%20%28x%29%20%3D%201-e%5E%7B-%5Clambda%20x%7D%5C%5CF_x%20%28x%29%20%3D%201-e%5E%7B-0.5x%7D)
Therefore, the probability that the repair time is more than 4 horus can be calculate as,
![P(x>4)=1-P(x4)= 1-F_x(4)\\P(x>4) = 1-e^{-0.5*4}\\P(x>4) = 1-0.98\\P(x>4) = 0.018](https://tex.z-dn.net/?f=P%28x%3E4%29%3D1-P%28x%3C4%29%5C%5CP%28x%3E4%29%3D%201-F_x%284%29%5C%5CP%28x%3E4%29%20%3D%201-e%5E%7B-0.5%2A4%7D%5C%5CP%28x%3E4%29%20%3D%201-0.98%5C%5CP%28x%3E4%29%20%3D%200.018)
The probability that the repair time is more than 4 hours is 0.136
b) The probability that repair time is at least 12 hours given that the repair time is more than 7 hoirs is calculated as,
![P(x\geq 12|x>7)=P(X\geq7+5|x>7)\\P(x\geq12|x>7)=P(X\geq5)\\P(x\geq12|x>7)=1-P(x\leq 5)\\P(x\geq12|x>7)=1-e^{-0.5(2)}](https://tex.z-dn.net/?f=P%28x%5Cgeq%2012%7Cx%3E7%29%3DP%28X%5Cgeq7%2B5%7Cx%3E7%29%5C%5CP%28x%5Cgeq12%7Cx%3E7%29%3DP%28X%5Cgeq5%29%5C%5CP%28x%5Cgeq12%7Cx%3E7%29%3D1-P%28x%5Cleq%205%29%5C%5CP%28x%5Cgeq12%7Cx%3E7%29%3D1-e%5E%7B-0.5%282%29%7D)
![P(x\geq 12|x>7)=0.6321](https://tex.z-dn.net/?f=P%28x%5Cgeq%2012%7Cx%3E7%29%3D0.6321)
The probability that repair time is at least 12 hours given that the repair time is more than 7 hours is 0.63
Answer:
Work done by the fluid in the piston=164.5kJ/kg
Specific gas constant= 0.263 kJ/kg K
Molecular weight of gas= 31.54 kmol
The function if I’m not correct just text me but 3
Answer:
R min = 28.173 ohm
R max = 1.55 ×
ohm
Explanation:
given data
capacitor = 0.227 μF
charged to 5.03 V
potential difference across the plates = 0.833 V
handled effectively = 11.5 μs to 6.33 ms
solution
we know that resistance range of the resistor is express as
V(t) =
...........1
so R will be
R =
....................2
put here value
so for t min 11.5 μs
R = ![\frac{11.5}{0.227\times ln(\frac{5.03}{0.833})}](https://tex.z-dn.net/?f=%5Cfrac%7B11.5%7D%7B0.227%5Ctimes%20ln%28%5Cfrac%7B5.03%7D%7B0.833%7D%29%7D)
R min = 28.173 ohm
and
for t max 6.33 ms
R max =
R max = 1.55 ×
ohm
Answer:
cant see the moon sorry dude