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insens350 [35]
3 years ago
7

A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted

on selected samples, but all components are also subjected to Vickers hardness testing. (A) What HV (in Kgf/mm2 ) is the minimum acceptable value? (B) If hardness is measured using Rockwell C hardness test, what is the minimum HRC value that is acceptable?
Engineering
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

a) The minimum acceptable value is 387.5 HV using Vickers hardness test.

b) The minimum acceptable value is 39.4 HRC using Rockwell C hardness test.

Explanation:

To get the tensile strength of a material from its hardness, we multiply it by an empirical constant that depends on things like yield strength, work-hardening, Poisson's ratio and geometrical factors. The incidence of cold-work varies this relationship.

According to DIN 50150 (a conversion table for hardness), the constant for Vickers hardness is ≈ 3.2 (an empirical approximate):

\mbox{Tensile strength}=HV*3.2\\\\HV  = \frac{\mbox{Tensile strength}}{3.2} =\frac{1240}{3.2}=387.5

According to DIN 50150, the constant for Rockwell C hardness test is ≈31.5 around this values of tensile strength:

\mbox{Tensile strength}=HRC*31.5\\\\HRC  = \frac{\mbox{Tensile strength}}{31.5} =\frac{1240}{31.5}=39.4

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vekshin1

Answer:

The solution code is written in Java.

  1.        Scanner input = new Scanner(System.in);
  2.        System.out.print("Enter operator: ");
  3.        String operator = input.nextLine();
  4.        System.out.print("Enter first integer: ");
  5.        int num1 = input.nextInt();
  6.        System.out.print("Enter second integer: ");
  7.        int num2 = input.nextInt();
  8.        int result = 0;
  9.        switch(operator){
  10.            case "+":
  11.               result = num1 + num2;
  12.               break;
  13.            case "-":
  14.                result = num1 - num2;
  15.                break;
  16.            case "*":
  17.                result = num1 * num2;
  18.                break;
  19.            case "/":
  20.                result = num1 / num2;
  21.                break;
  22.            default:
  23.                System.out.println("Invalid operator");
  24.        }
  25.        System.out.println(result);

Explanation:

To ask for the user input for two whole numbers and an operator, we can use Java Scanner class object. Since the input operator is a string, we can use nextLine() method to get the operator string (Line 3). We use nextInt() method to get whole number input (Line 5 & 7).

Next we use the switch keyword and pass the operator into the switch structure to determine which case statement should be executed. For example,  if the input operator is "*" the statement  "<em>result = num1 * num2;</em> " will run and multiply <em>num1</em> with <em>num2. </em>

3 0
4 years ago
In this unit, you looked at modern vehicle technology and the ad-
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Answer:Taking as a basis of calculation 100 mol of gas leaving the conversion reactor, draw andcompletely label a flowchart of this process. Then calculate the moles of fresh methanol feed,formaldehyde product solution, recycled methanol, and absorber off-gas, the kg of steamgenerated in the waste-heat boiler, and the kg of cooling water fed to the heat exchangerbetween the waste-heat boiler and the absorber. Finally, calculate the heat (kJ) that must beremoved in the distillation column overhead condenser, assuming that methanol enters as asaturated vapor at 1 atm and leaves as a saturated liquid at the same pressure.

1

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Explanation:

8 0
3 years ago
A 0.06-m3 rigid tank initially contains refrigerant- 134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve t
lesantik [10]

Answer:

a) 0.50613

b) 22.639 kJ

Explanation:

From table A-11 , we will make use of the properties of Refrigerant R-13a at 24°C

first step : calculate the  volume of R-13a  ( values gotten from table A-11 )

V = m1 * v1 = 5 * 0.0008261 = 0.00413 m^3

next : calculate final specific volume ( v2 )

v2 = V / m2 = 0.00413 / 0.25 ≈ 0.01652 m^3/kg

<u>a) Calculate the mass of refrigerant that entered the tank </u>

v2 = Vf + x2 * Vfg

v2 = Vf +  [ x2 * ( Vg - Vf ) ] ----- ( 1 )

where:  Vf = 0.0008261 m^3/kg, V2 = 0.01652 m^3/kg , Vg = 0.031834 m^3/kg  ( insert values into equation 1 above )

x2 = ( 0.01652 - 0.0008261 ) / 0.031834

     = 0.50613 ( mass of refrigerant that entered tank )

<u>b) Calculate the amount of heat transfer </u>

Final specific internal energy = u2 = Uf + ( x2 + Ufg ) ----- ( 2 )

uf = 84.44 kj/kg , x2 = 0.50613 , Ufg = 158.65 Kj/kg

therefore U2 = 164.737 Kj/kg

The mass balance  ( me ) = m1 - m2 --- ( 3 )

energy balance( Qin ) = ( m2 * u2 ) - ( m1 * u1 ) + ( m1 - m2 ) * he

therefore Qin = 41.184 - 422.2 + 403.655  = 22.639 kJ

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A clay sample has a wet mass of 417 g, a volume of 276 cm3, and a specific gravity of 2.70. When oven dried, the mass becomes 22
nataly862011 [7]

Answer:

a. WATER CONTENT.

mass of water (MW)= 417g - 225g

Mw= 192g

M= (Mw / Ms)

M= [192/417]

M= 0.46

M= 46.0%

b. Void Ration (e)

To calculate the void ratio we must first calculate the volume of solids. Then we can find the volume of voids by subtracting the volume of solids from the total volume.

Ps= (Ms/Vs)=GsPw

Therefore

Vs= (Ms/GsPw)

Vs= (417/ 2.70*1000)

Vs= 0.154cm3

But V= Vv+Vs

Vv=V-Vs

e= (Vv/Vs)

8 0
3 years ago
What is a jack plane used for​
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