Answer:
no not really
Explanation:
From your friendly neighborhood cereal killer,
Sir. BLOODPR1NCE
I think it would definitely be dinvi and the ghosts just because I really relate to that story
Answer:
<em>866.1 N</em>
Explanation:
The torque on the flywheel = 300 N-m
The force from the hydraulic cylinder will generate a moment on CA about point A.
The part of this moment that will be at point B about A must be proportional to the torque on the cylinder which is 300 N-m
we know that moment = F x d
where F is the force, and
d is the perpendicular distance from the turning point = 1 m
Equating, we have
300 = F x 1
F = 300 N this is the frictional force that stops the flywheel
From F = μN
where F is the frictional force
μ is the coefficient of static friction = 0.4
N is the normal force from the hydraulic cylinder
substituting, we have
300 = 0.4 x N
N = 300/0.4 = 750 N
This normal force calculated is perpendicular to CA. This actual force, is at 30° from the horizontal. To get the force from the hydraulic cylinder R, we use the relationship
N = R sin (90 - 30)
750 = R sin 60°
750 = 0.866R
R = 750/0.866 = <em>866.1 N</em>
Answer:
Single-point or throttle body injection. Port or multipoint fuel injection.
Answer:
The overflow rate is 4.24×10^-4 m/s.
The detention time is 7069.5 s
Explanation:
Overflow rate is given as volumetric flow rate ÷ area
volumetric flow rate = 0.3 m^3/s
area = πd^2/4 = 3.142×30^2/4 = 706.95 m^2
Overflow rate = 0.3 m^3/s ÷ 706.95 m^2 = 4.24×10^-4 m/s
Detention time = volume ÷ volumetric flow rate
volume = area × depth = 706.95 m^2 × 3 m = 2120.85 m^3
Detention time = 2120.85 m^3 ÷ 0.3 m^3/s = 7069.5 s