Answer: No, not in favor of the idea.
This is because, an increase in the refrigerator's work output is equal to work input. In real live application, the work input of the refrigerator is always greater than the additional work output. This will result to reducing the efficiency of the power plant.
Answer:
hello below is missing piece of the complete question
minimum size = 0.3 cm
answer : 0.247 N/mm2
Explanation:
Given data :
section span : 10.9 and 13.4 cm
minimum load applied evenly to the top of span : 13 N
maximum load for each member ; 4.5 N
lets take each member to be 4.2 cm
Determine the max value of P before truss fails
Taking average value of section span ≈ 12 cm
Given minimum load distributed evenly on top of section span = 13 N
we will calculate the value of by applying this formula
= = 1.56 * 10^-5
next we will consider section ; 4.2 cm * 0.3 cm
hence Z (section modulus ) = BD^2 / 6
= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8
Finally the max value of P( stress ) before the truss fails
= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )
= 0.247 N/mm2
Answer:
She is a aerospace engineer.
Explanation:
This is because she works is the aerospace industry, so she must be an aerospace engineer.
Answer: the reflection loss is 4%
Explanation:
Given that;
n for window glass is 1.5
we know that
Reflection Loss rλ = (nλ - 1)² / (nλ + 1)²
the reflection of loss rλ at normal incidence between two media with different refractive indexes rλ = n'/n, the ratio indices
where n is index of refraction of air ( 1 )
and n' is the refraction of window glass ( 1.5 )
our nλ is 1.5
so we substitute into the equation
rλ =[ (1.5 - 1)² / (1.5 + 1)²] × 100
= [0.25 / 6.25] × 100
= 0.04 × 100
= 4%
Therefore the reflection loss is 4%
Answer:
yield stress is when people do not want to have stress and they take it slow and proof stress is when the people look at the people having stress and when they say the dont they have proof.
Explanation: