Answer:
axial stress in bar B = 25Mpa.
Deformation of bar A = 0.4mm.
Explanation:
PS: Kindly check the attached picture for the diagram showing the two bars that is to say the bar A and the bar B.
So, we are given the following data or information or parameters which we are going to use in solving this particular question or problem. Here they are;
The cross-sectional areas of Bars A and B = 400 mm2, the modulus of elasticity of bar A and bar B = 200 GPa, applied force = 10kN.
STEP ONE: The first step is to determine or calculate the axial stress in bar B. Therefore,
Axial stress in bar B = 10 × 10³ ÷ 400 × 10⁻⁶ = 25 Mpa.
STEP TWO: The second step here is to determine or calculate the deformation of bar A. Therefore,
The deformation of bar A = 20 × 10³ ×1.5 ÷ 400 × 10⁻⁶ × 200 × 10³ = 0.375 mm.
Answer:
c
Explanation:
You never want short system terminals
Answer:
Explanation:
I do not have access to your diagram but based on what I know, a food web cannot sustain itself without decomposers. They are the main guys who break down dead animals, plants into organic or inorganic nutrients which are needed by the primary producers to grow. So if decomposers are not there then producers cannot produce and thus herbivores cannot live and carnovers die out as well. Hope this makes sense.
Check out: https://www.nationalgeographic.org/encyclopedia/decomposers/
Tell me why i got this question got it right and now won’t remember but i’ll get back at you when i remember
Answer:
1 13/64
Explanation:
The depth of the hole is the height of the block less the remaining material below the hole:
depth = 1 3/8 +1 15/16 - 3/8 = (1 3/8 -3/8) +1 15/16 = 2 15/16
We want to find the difference between this depth and the depth of the hole already drilled:
2 15/16 -1 47/64 = 2 60/64 -1 47/64
= (2 -1) +(60 -47)/64 = 1 13/64
The hole must be drilled 1 13/64 deeper to match the drawing.
