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3 years ago

If a is the least common multiple of 12, 24, and 36, and b is the lowest prime number, what is the sum of a and b

Mathematics

1 answer:

omeli [17]3 years ago

6 0

Answer:

Step-by-step explanation:

12=2×2×3

24=2×2×3

36=2×2×3×3

L.C.M.=2×2×3×3=36

lowest prime number=2

sum=36+2=38

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BRO SOMEONE PLEASE HELP ME OUT BRO I FR NEED SOME HELP. HOW DO YOU DO THIS

Finger [1]

Answer:

there you go bro. 168 degrees for each angle

Step-by-step explanation:

To calculate the central angle visualize a circle in the center of the polygon. A circle has 360 degrees. Divide 360 by the number of sides and that will tell you the central angle size. So 360 divided by 30 equals 18 degrees.

To find the base angle use this formula

180(n-2)/n where n is the number of sides of a regular polygon.

When you plug in 30 for n

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3 years ago

Naomi needs 2 cups of sugar for a cake she is baking she only has a 1/4 cup measuring cup how many times will Naomi need to feel

saul85 [17]

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3 years ago

Read 2 more answers

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$