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Ann [662]
3 years ago
12

Suppose you have an Avogadro's number of nitrogen atoms. How many grams does this represent? Enter your answer to one decimal pl

ace.
Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer:

2.3 x 10-23 g.

Explanation:

The mass of a single atom is the mass number, 14, is the mass in grams of one mole of carbon.

One mole of Nitrogen atom is 6.022 x 1023 atoms (Avogadro's number). This can then used to convert a nitogen atom to grams by the ratio:

mass of 1 atom / 1 atom = mass of a mole of atoms / 6.022 x 10^23 atoms.

mass of 1 atom = mass of a mole of atoms / 6.022 x 1023

mass of 1 N atom = 14 / 6.022 x 10^23 N atoms

mass of 1 N atom = 2.325 x 10^-23 g

The mass of a single Nitrogen atom is 2.325 x 10-23 g.

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2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​
Sophie [7]
<h3>Answer:</h3>

\displaystyle 0.5 \ mol \ CO_2

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                        \displaystyle 0.5 \ mol \ CO_2
7 0
2 years ago
A megamole of titanium contains __________ moles of titanium.
Gala2k [10]
Answer is: 1 megamole is equal to 1000000 (one million) mole or 10⁶<span> moles</span>.
The SI base unit for amount of substance is the mole. The SI prefix "mega" represents a factor of 10⁶, or in exponential notation, 1E6.
<span>The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 12 grams of carbon C-12.</span>

8 0
3 years ago
Read 2 more answers
The temperature of a gas rose from 250K to 350K. At 350K, the volume of the gas was 3.0L. If the pressure did not change, what w
LenaWriter [7]
Hey there,

So. . I believe is how you do it. I did 350 x 3.0 and it got me 1,050.
We always multiply it by when it come to the initial volume of the gas.

Hope this helps.

~Jurgen<span />
7 0
3 years ago
Read 2 more answers
You are working in your laboratory and decide to do some cleaning. You find a test tube with some brown substance congealed at t
Anna [14]

Answer:

  • <em>The mystery substance is</em> <u>C. Bromine (Br) </u>

Explanation:

<em>Argon (Ar) </em>is a noble gas. Whose freezing point is -189 °C (very low), thus it cannot be the frozen substance. Also, it is not reactive, thus is would have not reacted with iron. Hence, argon is not the mystery substance.

<em>Scandium (Sc) </em>is a metal from group 3 of the periodic table, thus is will not react with iron. Thus, scandium is not the mystery substance.

Both <em>bromine</em> and <em>iodine</em> are halogens (group 17 of the periodic table).

The freezing point of bromine is −7.2 °C, ​and the freezing point of iodine is 113.7 °C. Thus, both could be solids (frozen) in the lab.

The reactivity of the halogens decrease from top to bottom inside the group. Bromine is above iodine. Then bromine is more reactive than iodine.

Bromine is reactive enough to react with iron. Iodine is not reactive enough to react with iron.

You can find in the internet that bromine vapour over hot iron reacts  producing iron(III) bromide. Also, that bromine vapors are red-brown.

Therefore, <em>the mystery substance is bromine (Br).</em>

7 0
3 years ago
How is the molarity affected if some solution splashes out of the flask during titration?
Jobisdone [24]

Answer:

not affected?

Explanation:

pretty sure M / concentration isn't affected, only volume.

5 0
2 years ago
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