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3 years ago

6. Soap contains 76.5% C, 11.3% O, and 12.2% H and the MW = 847, what is the

Chemistry

1 answer:

vlada-n [284]3 years ago

3 0

Answer:

the molecular formula of the soap is C₅₄H₁₀₂O₆

Explanation:

Given;

composition of carbon, C = 76.5%

composition of oxygen, O = 11.3%

Composition of hydrogen, H = 12.2%

The empirical formula is calculated as follows;

C: 76.5% / 12 O: 11.3% / 16 H: 12.2% / 1

= 6.375 = 0.706 = 12.2

Divide through by the least number (0.706);

= 6.375/0.706 = 0.706 / 0.706 = 12.2 / 0.706

= 9 = 1 = 17

The empirical formula = C₉H₁₇O

The molecular formula is calculated as follows;

(C₉H₁₇O)n = 847

(9 x 12 + 17 x 1 + 16 x 1)n = 847

(108 + 17 + 16)n = 847

141n = 847

n = 847/141

n = 6

The molecular is (C₉H₁₇O)6 = C₅₄H₁₀₂O₆

Therefore, the molecular formula of the soap is C₅₄H₁₀₂O₆

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$W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}$

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