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podryga [215]
3 years ago
5

6. Soap contains 76.5% C, 11.3% O, and 12.2% H and the MW = 847, what is the

Chemistry
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

the molecular formula of the soap is C₅₄H₁₀₂O₆

Explanation:

Given;

composition of carbon, C = 76.5%

composition of oxygen, O = 11.3%

Composition of hydrogen, H = 12.2%

The empirical formula is calculated as follows;

C:    76.5% / 12          O:  11.3% / 16             H:   12.2% / 1

     =  6.375                  =   0.706                   =  12.2

Divide through by the least number (0.706);

    =  6.375/0.706           = 0.706 / 0.706          =  12.2 / 0.706

   =  9                              =    1                              =  17

The empirical formula = C₉H₁₇O

The molecular formula is calculated as follows;

(C₉H₁₇O)n = 847

(9 x 12    +   17 x 1      +  16 x 1)n   = 847

(108 + 17 + 16)n = 847

141n = 847

n = 847/141

n = 6

The molecular is (C₉H₁₇O)6 =  C₅₄H₁₀₂O₆

Therefore, the molecular formula of the soap is C₅₄H₁₀₂O₆

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LekaFEV [45]

Solution: Sentence D is a scientific statement.

Scientific statement is a statement that defines the science behind any situation. There should be any experimental result or observation to state any scientific statement. Also, the statement should be accepted by considering other scientific aspects.

Here, statement A can not be a scientific statement as different aromas of cooked food are liked by different people. Any one can find aroma of cooked food in copper better than the ceramic pot.

Thus, the statement can be proved wrong easily.

Statement B can not be a scientific statement as people can find the taste of normal water (without ice cubes) better than the ice cold water.

Statement C is not a scientific statement as there is no science behind watching baseball or ice hockey, it depends on the liking of today's people.

Statement D is a scientific statement because this can be scientifically proved.  

5 0
4 years ago
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I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb 2+ and 0.0050 M Ag +. [K sp (PbI 2) = 1.4 × 10 –8; K sp (A
UkoKoshka [18]

Answer:

[Ag⁺] = 5.0x10⁻¹⁴M

Explanation:

The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:

Ksp(PbI₂) = [Pb²⁺] [I⁻]² = 1.4x10⁻⁸

Ksp(AgI) = [Ag⁺] [I⁻] = 8.3x10⁻¹⁷

The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

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6 0
3 years ago
The compound dioxane, which is used as a solvent in various industrial processes is composed of C,H, and O atoms. Combustion of
Lady_Fox [76]

Answer:

The correct formula of dioxane is C₄H₈O₂.

Explanation:

Given data:

mass of dioxane= 2.23 g

mass of water = 1.802 g

mass of carbon dioxide = 4.401 g

molar mass of dioxane = 88.1 g / mol

Molecular formula of dioxane = ?

Solution:

percentage of carbon = (4.401 g/2.23 g ) × (12 /44) × 100

                                     =  (1.98 × 0.273) × 100 = 54.1

percentage of hydrogen =  (1.802 g/ 2.23 g) × (2.016 /18.016) × 100

                                         = (0.81 × 0.112) × 100 = 9.072

percentage of oxygen = 100 - (54.1 + 9.072)

                                     = 100 - 63.172 = 36.828

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 54.1 /12 = 4.51

No. of gram atoms of hydrogen = 9.072 / 1.008 = 9

No. of gram atoms of oxygen = 36.828 / 16 = 2.302

Atomic ratio:

    C :H :O               4.51/ 2.302    :   9 / 2.302   :  2.302 /2.302

    C :H :O                2 : 4 : 1

Molecular formula:

   Molecular formula = n × (empirical formula)

   n = molar mass of compound / empirical formula mass

   empirical formula mass= 2 × 12 + 4 × 1.008  + 1 × 16

    empirical formula mass= 24+ 4.032 +16 = 44.032

                 n = 88.1 / 44.032 = 2

        Molecular formula = n × (empirical formula)

        Molecular formula = 2 × (C₂H₄O)

         Molecular formula = C₄H₈O₂

8 0
3 years ago
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5 0
4 years ago
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