Question

6. Soap contains 76.5% C, 11.3% O, and 12.2% H and the MW = 847, what is the

Answer 1

Answer:

the molecular formula of the soap is C₅₄H₁₀₂O₆

Explanation:

Given;

composition of carbon, C = 76.5%

composition of oxygen, O = 11.3%

Composition of hydrogen, H = 12.2%

The empirical formula is calculated as follows;

C:    76.5% / 12          O:  11.3% / 16             H:   12.2% / 1

     =  6.375                  =   0.706                   =  12.2

Divide through by the least number (0.706);

    =  6.375/0.706           = 0.706 / 0.706          =  12.2 / 0.706

   =  9                              =    1                              =  17

The empirical formula = C₉H₁₇O

The molecular formula is calculated as follows;

(C₉H₁₇O)n = 847

(9 x 12    +   17 x 1      +  16 x 1)n   = 847

(108 + 17 + 16)n = 847

141n = 847

n = 847/141

n = 6

The molecular is (C₉H₁₇O)6 =  C₅₄H₁₀₂O₆

Therefore, the molecular formula of the soap is C₅₄H₁₀₂O₆