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ella [17]
3 years ago
15

A ball dropped from a height of 50 meters, Determine the speed of the ball after 3 seconds

Physics
1 answer:
Alex17521 [72]3 years ago
8 0

16.7 m/s

<em>To</em><em> </em><em>deter</em><em>mine</em><em> </em><em>the </em><em>speed</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>formula</em><em>:</em><em> </em><em>Dista</em><em>nce</em><em> </em><em>÷</em><em> </em><em>Time</em><em> </em><em>so</em><em>,</em><em> </em><em>5</em><em>0</em><em> </em><em>÷</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>6</em><em>.</em><em>6</em><em>6</em><em>.</em><em>.</em><em>.</em><em> </em><em>(</em><em> </em><em>rounde</em><em>d</em><em> </em><em>off</em><em> </em><em>to</em><em> </em><em>1</em><em>.</em><em>d</em><em>.</em><em>p</em><em> </em><em>is</em><em> </em><em>1</em><em>6</em><em>.</em><em>7</em><em>)</em><em>.</em>

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A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
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garik1379 [7]
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5 0
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When heating a liquid in a test tube, which of the following safety precautions should you take?. . 1.Wear latex gloves.. 2. Hea
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8 0
3 years ago
Read 2 more answers
A train crosses a bridge that is 1300 m long in 1 minute and 5 seconds.
Nat2105 [25]

Answer:

I'm pretty sure it's 20m/s because 1300m divided by 65 seconds is 20 so I think it's 20m/s

Explanation:

3 0
2 years ago
It takes 15 min to drive 6.0 mi in a straight line to the local hospital. It takes 10 min to go the last 3.0 mi, 2.0 min to go t
Gala2k [10]

Answer:

36.87 km/h

Explanation:

Convert all the units in SI system

1 mile = 1609.34 m

d1 = 6 mi = 9656.04 m

t1 = 15 min = 15 x 60 = 900 s

d2 = 3 mi = 4828.02 m

t2 = 10 min = 10 x 60 = 600 s

d3 = 1 mi = 1609.34 m

t3 = 2 min = 2 x 60 = 120 s

d4 = 0.5 mi = 804.67 m

t4 = 0.5 min = 0.5 x 60 = 30 s

Total distance, d = d1 + d2 + d3 + d4

d = 9656.04 + 4828.02 +  1609.34 + 804.67 = 16898.07 m = 16.898 km

total time, t = t1 + t2 + t3 + t4

t = 900 + 600 + 120 + 30 = 1650 s = 0.4583 h

The ratio of the total distance covered to the total time taken is called average speed.

Average speed = 16.898 / 0.4583 = 36.87 km/h

6 0
3 years ago
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