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svet-max [94.6K]
3 years ago
8

Which of the following descriptions apply to the Milky Way galaxy

Physics
2 answers:
Llana [10]3 years ago
6 0
You didn’t give me descriptions, but I’ll describe the Milky Way anyway
It is 100 thousand light years in diameter
It is a huge cloud of star creating gas
We live in it
It is a spiral galaxy
Hopefully this helped ☺️
xenn [34]3 years ago
3 0
Where are the choices?
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An 800 kg fishing boat going south at 12 m/s runs into a stopped pontoon boat (1400 kg). The boats stick together and move south
kykrilka [37]

Answer:

the velocity of the boats after the collision is 4.36 m/s.

Explanation:

Given;

mass of fish, m₁ = 800 kg

mass of boat, m₂ = 1400 kg

initial velocity of the fish, u₁ = 12 m/s

initial velocity of the boat, u₂ = 0

let the final velocity of the fish-boat after collision = v

Apply the principle of conservation of linear momentum for inelastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

800 x 12    +   1400 x 0 = v(800 + 1400)

9600 = 2200v

v = 9600/2200

v = 4.36 m/s

Therefore, the velocity of the boats after the collision is 4.36 m/s.

7 0
3 years ago
não é difícil de perceber uma relação aditiva entre os termos consecutivos (1;3;6;10...)(A)qual é o sexto e décimo número triang
EastWind [94]
It is 15 and 45 ............
7 0
3 years ago
1. What could scientists learn by using the Law of Superposition?
Juli2301 [7.4K]
Answer C. 1.scientists learn by using the law of superposition B
7 0
3 years ago
Read 2 more answers
To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a
irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

                                                                                                               = 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

                                           W = F x S    joules

Substituting the values in the above equation

                                            W = 1.5 x 10⁶  x  355 · sin θ

                                                = 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J                        

6 0
3 years ago
You throw a ball downward from a window at a speed of 2.0m/s. How far has it fallen in 3 seconds?
bekas [8.4K]
Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling.
a=9.81 m/s^2
Vi= 2 m/s
t= 3 x

we use the formula
d = (Vi)(t) + (1/2)(a)(t)^2
d= (2)(3) + (1/2)(9.81)(9)
d=50.145 m
3 0
3 years ago
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