Which electron dot diagram represent H2

A bicycle pump contains 250 mL of air at a pressure of 102 kPa. If the pump is

CaHeK987 [17]

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

<h3>Boyle's law</h3>

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

P1= 102 kPa= 10335.1 atm (being 1 kPa= 101.325 atm)
V1= 250 mL
P2= 2.25 atm
V2= ?

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

1,148,344.444 mL= 1148.34 L= V2

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

Learn more about Boyle's law:

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3 0

2 years ago

A mixture of NaBrO 3 , NaBrO3, NaHCO 3 , NaHCO3, Na 2 CO 3 , Na2CO3, and NaBr NaBr was heated, producing H 2 O , H2O, CO 2 , CO2

nata0808 [166]

Answer:

Composition of initial mixture is:

9.02g of NaBrO₃

15.84g of Na₂CO₃

17.06g of NaHCO₃

82.58g NaBr

Explanation:

For the reactions:

2NaBrO₃(s) ⟶ 2NaBr(s) + 3O₂(g)

2NaHCO₃(s) ⟶ Na₂O(s) + H₂O(g) + 2CO₂(g)

Na₂CO₃(s) ⟶ Na₂O(s)+CO₂(g)

All H₂O(g) comes from NaHCO₃. Thus, initial moles and mass of NaHCO₃ are:

1.83g H₂O ₓ (1 mol H₂O / 18.02g) ₓ (2 mol NaHCO₃ / 1 mol H₂O) = 0.203moles NaHCO₃ ₓ (84g / 1mol NaHCO₃) =

17.06g of NaHCO₃

CO₂ comes from NaHCO₃ and Na₂CO₃.

15.51g of CO₂ are:

15.51g CO₂ ₓ (1mol / 44.01g) = 0.352moles of CO₂

As 2 moles of NaHCO₃ produce 2 moles of CO₂, moles of CO₂ that comes from NaHCO₃ are 0.203moles NaHCO₃. Moles of CO₂ that comes from Na₂CO₃ are:

0.352mol CO₂ - 0.203mol CO₂ = 0.149mol CO₂

These moles of CO₂ are produced from:

0.149mol CO₂ ₓ (1 mol Na₂CO₃ / 1 mol CO₂) ₓ (106g / 1mol Na₂CO₃) =

15.84g of Na₂CO₃

And all O₂ comes from NaBrO₃. Initial mass of NaBrO₃ is:

2.87g O₂ ₓ (1 mol O₂ / 32g) ₓ (2 mol NaBrO₃ / 3 mol O₂) ₓ (150.9g / 1mol NaBrO₃) =

9.02g of NaBrO₃

If initial mass of the mixture was 124.5g, mass of NaBr was:

124.5g - 9.02g of NaBrO₃ - 15.84g of Na₂CO₃ - 17.06g of NaHCO₃ =

82.58g NaBr

Composition of initial mixture is:

9.02g of NaBrO₃

15.84g of Na₂CO₃

17.06g of NaHCO₃

82.58g NaBr

5 0

4 years ago

What causes the rock layers of mountains to form zigzag shape?

creativ13 [48]

Answer =B) folding of rock

4 0

3 years ago

On a small farm, the weights of eggs that young hens lay are normally distributed with a mean weight of 51.3 grams and a standar

Lelechka [254]

Answer:

83.85% of the population is between 46.5g and 65.7g

Explanation:

the 68-95-99.7 rule states that the probability that a random variable (X=Weights of the eggs) is found inside 1 standard deviation , 2 standard deviations and 3 standard deviations from the mean is 68% , 95% , 99.7% respectively

then calling Z to

Z= (X-μ)/σ

where μ= mean , σ = standard deviation , then

for X₁=46.5g

Z₁= (X₁-μ)/σ = (46.5g - 51.3g)/4.8 g= -1

1 standard deviation from both sides (±1) = 68%

then since the normal distribution is symmetrical

1 standard deviation from one side (±1) = 68%/2 = 34%

for X₂=46.5g

Z₂= (X₂-μ)/σ = (65.7 g - 51.3g)/4.8 g= +3

3 standard deviation from both sides (±1) = 99.7%

then since the normal distribution is symmetrical

3 standard deviation from one side (±1) = 99.7%/2 = 49.85%

then

between -1 standard deviation from the mean and +3 standard deviations from the mean there is= 34% + 49.85% = 83.85% of the population (since the regions do not overlap each other)

8 0

3 years ago

6. The Earth’s electric field is directed vertically downward; at the ground level its strength is E = 130 N/C, and at an altitu

Alexxx [7]

Answer:

5.31x10⁻⁶ C

Explanation:

The cube is located 100 m altitude from the ground, so the superior face is at 100m and has E = 70 N/C, and the inferior face is at the ground with E = 130 N/C.

The electric field is perpendicular to the bottom and the top of the cube, so the total flux is the flux at the superior face plus the flux at the inferior face:

Фtotal = Ф100m + Фground

Where Ф = E*A*cos(α). α is the angle between the area vector and the field (180° at the topo and 0° at the bottom):

Фtotal = E100*A*cos(180°) + Eground*A*cos(0°)

Фtotal = 70A*(-1) + 130*A*1

Фtotal = 60A

By Gauss' Law, the flux is:

Фtotal = q/ε, where q is the charge, and ε is the permittivity constant in vacuum = 8.854x10⁻¹² C²/N.m²

A = 100mx100m = 10000 m²

q = 60*10000*8.854x10⁻¹²

q = 5.31x10⁻⁶ C

8 0

3 years ago