All categories

3 years ago

Why do Group 12 elements have different properties than Group 13 elements?

1 answer:

6 0

Group 12 Elements have two valence electrons while Group 13 Elements have three valence electrons.
Number of valence electrons tend to determine factors like reactivity. So elements with different number of valence electrons will have different properties.
That is why G12 and G13 have different properties

You might be interested in

A 10.0 g sample of a hydrate was heated until all the water was driven off. The mass of the anhydrous product remaining was 8.00

chubhunter [2.5K]

Answer:

20%

Explanation:

10.0 = 100%

8.00 = 80%

100-80= 20

3 0

3 years ago

2P4O10 + 2H2O → 2H3PO4

patriot [66]

Answer:

$\huge\red{ \mid{ \underline{ \overline{ \tt ♡ FORMULA: ♡ }} \mid}}$

2P4O10 + 2H2O → 2H3PO4

Balanced Equation → P4O10 + 6H2O → 4H3PO4

Tetraphosphorus Decaoxide + Water → Phosphoric Acid

${\huge\pink{\fbox{{࿐REACTION࿐}}}}$

Reaction Type → Synthesis

6 0

3 years ago

Read 2 more answers

In the reaction between Li and O, there is a transfer of electrons making an ionic bond. In the bond, lithium would be a (n) bec

galben [10]

Answer:

C) cation, loses, anion, gains

Explanation:

Lithium is a metal from Group 1, so it has 1 valence electron. Thus, it loses 1 electron to complete its octet and form the cation Li⁺.

Oxygen is a nonmetal from Group 16, so it has 6 valence electrons. Thus, it gains 2 electrons to complete its octet and form the anion O²⁻.

In the reaction between Li and O, there is a transfer of electrons making an ionic bond. In the bond, lithium would be a cation because it loses an electron, and oxygen would be an anion because it gains 2 electrons.

6 0

4 years ago

What is the atomic size going across a period (left or right)? what causes this trend?

natka813 [3]

The atomic size decreases; this is because as you go across the period, more electrons are found in the outer shell. As more electrons are added, the more attraction there is between the protons, in the nucleus, and the electrons, making the atom smaller.
Hope this helps!

5 0

3 years ago

If 24.3 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over?2 NO (g) + O₂ (g) → 2

zhuklara [117]

Explanation:

2 NO (g) + O₂ (g) ----> 2 NO₂ (g)

24.3 g of NO are reacting with 13.8 g of O₂. First we can convert the mass of theses samples into moles using their molar masses.

molar mass of O = 16.00 g/mol

molar mass of N = 14.01 g/mol

molar mass of NO = 16.00 g/mol + 14.01 g/mol

molar mass of NO = 30.01 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

moles of NO = 24.3 g * 1 mol/(30.01 g)

moles of NO = 0.810 moles

moles of O₂ = 13.8 g * 1 mol/(32.00 g)

moles of O₂ = 0.431 moles

Now, to determine the limiting reactant or the excess reactant we can find the number of moles of O₂ that will react with 0.810 moles of NO and the number of moles of NO that will react with 0.431 moles of O₂.

According to the coefficients of the reaction 2 moles of NO will react with 1 mol of O₂. Let's use that relationship to find the limiting reagent.

2 moles of NO = 1 mol of O₂

moles of O₂ = 0.810 moles of NO * 1 mol of O₂/(2 moles of NO)

moles of O₂ = 0.405 moles

moles of NO = 0.431 moles of O₂ * 2 moles of NO/(1 mol of O₂)

moles of NO = 0.862 moles

We found that we need 0.405 moles of O₂ to completely react with 0.810 moles of NO. Or, we need 0.862 moles of NO to completely react with ours 0.431 moles of NO.

We can say that NO is limiting our reaction and O₂ is in excess.

Only 0.405 moles of O₂ will react with 0.810 moles of NO. But we had 0.431 moles of it. Let's find the excess.

Excess of O₂ = 0.431 moles - 0.405 moles

Excess of O₂ = 0.026 moles

Answer: 0.026 moles is the number of moles of oxygen that will be left over.

4 0

1 year ago