<span>The correct answer is electron-cloud model. This model states that electrons don't go around in an eliptical way but rather completely erratically and uncontrolably and this is why it can't be known where they are or how they will behave. They form sort of like a cloud of many electrons that move erratically so you have to check it to see where it is.</span>
Answer:
49.4 g Solution
Explanation:
There is some info missing. I think this is the original question.
<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g available of a 40.5 % w/w solution of acetic acid in acetone. </em>
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Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>
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We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.

Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:

1. 100.67
2. 168.55
3. 2.747
So I’m not sure if 2 or 3 are right sorry
Answer:
- <em><u>pH </u></em><u>= 9.73</u>
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Explanation:
<em>pOH</em> is the negative logarithm of the molar <em>concentration</em> of<em> hydroxide ions </em>and pH is the negative logarithm of the concentration of hydronium ions.
The mathematical expression to determine pOH is:
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
Where [OH⁻] means the molar concentration of hydroxide ions.
Substituting:


<em>pH </em>and <em>pOH</em> are related by the equation:

From which:

Answer:
-2,044.0 kJ/mol
Explanation:
<em> I just did the test on edg</em>
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