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2 years ago

PLEASE HELPPP 100 POINTS!!

Chemistry

1 answer:

MissTica2 years ago

7 0

Answer:

1) pentane is of higher Molecular mass than propane hence heavier member

2) due to intermolecular hydrogen bonding methanol is liquid having lower molecular weight

3) I) in methanol C = sp3

ii) in methanoic acid C= sp2

5)I) i) The two carbon-oxygen bonds in the methanoate anion, HCO2-, have the same length due to resonance stabilization of the C-O bond

Explanation:

See attachment for question 4

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Select a depiction of a gas sample, as described by kinetic molecular theory, containing equal molar amounts of helium, neon, an

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2 years ago

Consider the following reaction at equilibrium: 2 NH3(g) ⇄ N2(g) + 3 H2(g) What does Le Chatelier's principle predict will happe

BabaBlast [244]

Answer : The equilibrium will shift in the left direction.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

The given reaction is:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

As per question, when we are adding $N_2$ then the concentration of $N_2$ is increased on product side then the equilibrium will shift in the direction where decrease of concentration of $N_2$ takes place. Therefore, the equilibrium will shift in the left direction.

Thus, the equilibrium will shift in the left direction.

7 0

3 years ago

Helppppp asaapppppp plzzzzzz

Gala2k [10]

Answer:

Alright the very first thing you need to do is balance the equation:

2HCl + Na2CO3 -----> 2NaCl + CO2 + H2O

Now we need to find the limiting reactant by converting the volume to moles of both HCl and Na2CO3.

Volume x Concentration/molarity = moles

0.235L x 0.6 M = 0.141 moles / molar ratio of 2 = 0.0705 moles of HCl

0.094L x 0.75 M = 0.0705 moles /molar ratio of 1 = 0.0705 moles of Na2CO3

Since both of the moles are equal, it means the entire reaction is complete (while the identification of limiting reactant may seem like an unnecessary step, it's quite essential in stoichiometry, so keep an eye out) and there is no excess of any reactant.

Now we know that the product we want to calculate is aqueous so, following the law of conservation of mass, we should add both volumes together to calculate how much volume we could get for NaCl.

0.235 + 0.094 = 0.329L of NaCl

Now we apply the C1V1 = C2V2 equation using the concentration and volume of Na2CO3 because it's molar ratio is one to one to NaCl (You can also use HCL, but you have to divide their moles by 2 for the molar ratio) and the volume we just calculated for NaCl.

(0.75M) x (0.094L) = C2 x (0.329L)

Rearrange equation to solve for C2:

(0.75M) x (0.094L) = C2

(0.329L)

C2 = 0.214 M (Rounded)

When the reaction is finished, the NaCl solution will have a molarity concentration of 0.214 M.

7 0

1 year ago

SHOW WORK

horsena [70]

10.0gNaCl/2.0Lsolution= 5.0g/L

4 0

3 years ago

Which two compounds are classified as bases by the Brønsted-Lowry definition, but not by the Arrhenius definition, and why?

konstantin123 [22]

Answer: Ammonia (NH3) and sodium carbonate (Na2CO3), because they accept hydrogen ions but lack hydroxide ions.

Explanation:

i took the test and got it correct :) hope this helps

6 0

2 years ago