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andriy [413]
3 years ago
15

PLEASE HELPPP 100 POINTS!!

Chemistry
1 answer:
MissTica3 years ago
7 0

Answer:

1) pentane is of higher Molecular mass than propane hence heavier member

2) due to intermolecular hydrogen bonding methanol is liquid having lower molecular weight

3) I) in methanol C = sp3

ii) in methanoic acid C= sp2

5)I) i) The two carbon-oxygen bonds in the methanoate anion, HCO2-, have the same length due to resonance stabilization of the C-O bond

Explanation:

See attachment for question 4

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It takes 2,267 joules of heat to raise the temperature of a 44.5 gram sample of a metal from 33.9°C to 288.3°C. What is the heat
ehidna [41]

Answer:

\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

Explanation:

The formula for the amount heat q absorbed by a substance is

q = mcΔT

where

 m = the mass of the substance

  C = the specific heat capacity of the material

ΔT = the temperature change

Data:

 q = 2267 J

m = 44.5 g

T₁ = 33.9 °C

T₂ = 288.3 °C

Calculations:

ΔT = (288.3 - 33.9) °C = 254.4 °C

\begin{array}{rcl}2267 & = & 44.5 \times C \times 254.4\\2267 & = & 11 180C\\C& = & \dfrac{2267}{11180}\\\\& = & \textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}\\\end{array}

\text{The specific heat capacity of the metal is \boxed{\textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

5 0
3 years ago
In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.
DaniilM [7]

Answer:

0.2 M.

Explanation:

  • For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

  • For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

  • For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

5 0
3 years ago
What do all acids start with?
velikii [3]

Hydrogen

...

Acids always dissociate in water, which causes the production of hydrogen ions. Not all necessarily <em>start</em> with hydrogen, but most do and all contain.

5 0
3 years ago
Read 2 more answers
We are all familiar with the general principles of operation of an internal combustion engine: the combustion of fuel drives out
Alexus [3.1K]

Answer:

The work done by the system is 100 J

Explanation:

Given details

The cross sectional area of the of the container is A = 100.0 cm^2 = 0.01m²

The total distance pushed by the piston is d = 10 cm = 0.10m

The total external pressure by which piston pushed is P = 100 kPa

From above data, the following relation can be used to determine the change in volume of the container

∆V = A * d

∆V = 0.01 * 0.10 = 0.001 m³

By using the following relation, the work done by the system is calculated as;

Work done W = P * ∆V

W = 100 * 0.001 = 0.1 kJ = 100 J

The work done by the system is 100 J

7 0
3 years ago
A source of zinc metal can be zinc ore containing zinc(II) sulfide. The ore is roasted in pure oxygen to produce the oxide and t
morpeh [17]

Answer:

32.7 grams of Zn will remained in the crucible after cooling.

Explanation:

2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2..[1]

ZnO+C\rightarrow Zn+CO..[2]

Adding [1] + 2 × [2] we get:

2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2..[3]

Moles of ZnS in crucible = 0.50 mol

According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.

Then 0.50 moles of ZnS will give:

\frac{2}{2}\times 0.50 mol=0.50 mol of Zn.

Mass of 0.50 moles of Zn =

= 0.50 mol × 65.4 g/mol =32.7 g

32.7 grams of Zn will remained in the crucible after cooling.

5 0
4 years ago
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