Answer:

Explanation:
The formula for the amount heat q absorbed by a substance is
q = mcΔT
where
m = the mass of the substance
C = the specific heat capacity of the material
ΔT = the temperature change
Data:
q = 2267 J
m = 44.5 g
T₁ = 33.9 °C
T₂ = 288.3 °C
Calculations:
ΔT = (288.3 - 33.9) °C = 254.4 °C


Answer:
0.2 M.
Explanation:
- For the acid-base neutralization, we have the role:
The no. of millimoles of acid is equal to that of the base at the neutralization.
<em>∴ (XMV) KOH = (XMV) H₂SO₄.</em>
X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),
M is the molarity.
V is the volume.
X = 1, M = 0.5 M, V = 38.74 mL.
X = 2, M = ??? M, V = 50.0 mL.
∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.
Hydrogen
...
Acids always dissociate in water, which causes the production of hydrogen ions. Not all necessarily <em>start</em> with hydrogen, but most do and all contain.
Answer:
The work done by the system is 100 J
Explanation:
Given details
The cross sectional area of the of the container is A = 100.0 cm^2 = 0.01m²
The total distance pushed by the piston is d = 10 cm = 0.10m
The total external pressure by which piston pushed is P = 100 kPa
From above data, the following relation can be used to determine the change in volume of the container
∆V = A * d
∆V = 0.01 * 0.10 = 0.001 m³
By using the following relation, the work done by the system is calculated as;
Work done W = P * ∆V
W = 100 * 0.001 = 0.1 kJ = 100 J
The work done by the system is 100 J
Answer:
32.7 grams of Zn will remained in the crucible after cooling.
Explanation:
..[1]
..[2]
Adding [1] + 2 × [2] we get:
..[3]
Moles of ZnS in crucible = 0.50 mol
According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.
Then 0.50 moles of ZnS will give:
of Zn.
Mass of 0.50 moles of Zn =
= 0.50 mol × 65.4 g/mol =32.7 g
32.7 grams of Zn will remained in the crucible after cooling.