Ask question

Ask question

All categories

3 years ago

13

A circular horizontal surface having an area of 1020.5 mm2that is completely immersed in a fluid experiences a uniform force of

1.06 mN. The pressure applied by the fluid on this surface is

1 answer:

Bingel [31]3 years ago

3 0

Answer:

Faya vei Abhikesh brass hahahahahaha

Explanation:

You might be interested in

What happens to the current in a circuit if a 1.5 volt battery

Alexus [3.1K]

Answer:

the current will improve in performance and tell me if im correct

4 0

3 years ago

If g were 15 instead of 9.81, what would your quads look like?

Jlenok [28]

Answer:

Quads will have more energy

Explanation:

If the acceleration due to gravity increases from 9.81 to 15, then the velocity will increase as the rate of changing velocity i.e acceleration has increased from 9.81 to 15 m/s^2

With increase of velocity, the energy and force will also increase. Hence, the squad will require/have higher energy.

5 0

2 years ago

A 35 kg boy is riding a 65 kg go-cart. He pushes on the gas pedal, causing the cart to accelerate at 5 m/s2. Use the equation F

trasher [3.6K]

Answer:

$\boxed {\boxed {\sf 500 \ Newtons }}$

Explanation:

The equation for force is given:

$F=m*a$

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.

total mass= boy's mass + go cart's mass

The boy's mass is 35 kilograms and the go cart's is 65 kilograms.

total mass= 35 kg+ 65 kg=100 kg

Now we know the total mass and the acceleration.

$m= 100 \ kg \\a= 5 \ m/s^2$

Substitute the values into the formula.

$F=100 \ kg * 5 \ m/s^2$

Multiply.

$F= 500 \ kg*m/s^2$

1 kilograms meter per square second is equal to 1 Newton.
Our answer of 500 kg*m/s² is equal to 500 Newtons.

$F= 500 \ N$

The force exerted by the go cart engine is <u>500 Newtons.</u>

4 0

2 years ago

Read 2 more answers

What molecule(s) does carbon, hydrogen, and oxygen come from?

Hunter-Best [27]

The molecule they all come from is water molecule

7 0

3 years ago

A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, $\Delta t=0.003\ s$

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

$F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N$

So, the average force on ball by the golf club is 340 N.

4 0

3 years ago