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3 years ago

Drag the item from the item bank to its corresponding match.

Physics

2 answers:

vlada-n [284]3 years ago

4 0

1 = 1
2 = 2
3 = 1
4 = 3
5 = 2
6 = 3

tigry1 [53]3 years ago

3 0

1- first law
2- third law
3- first law
4- second law
5- third law
6- second law

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A book is resting on the table. Forces are exerted _____.

scoray [572]

Forces are exerted I believe : all of the above
The action force might be Tyler throwing the ball
I don't know the last one

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3 years ago

Read 2 more answers

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s' for 10 secon

MArishka [77]

Answer:

Distance of 400m.

Explanation:

Use your kinematics equation to solve for distance (we can use kinematics b/c acceleration is constant).

d = (initial velocity x time) + 1/2 at^2

d = (20 x 10) + 1/2 (4) (10)^2

d = 200 + 200

d = 400 m

5 0

2 years ago

Pls hurry worth 28 points <3

Kipish [7]

Answer:

Explanation:

I will GUESS that we're supposed to be looking at a plot of a position in time.

IF that is the case.

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6 0

3 years ago

A skydiver of 75 kg mass has a terminal velocity of 60 m/s. At what speed is the resistive force on the skydiver half that when

ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, $V_T = 60 \ m/s$

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

$F_D = kV_T^2$

Where;

k is a constant

$k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}$

When the new drag force is half of the original drag force;

$F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}= \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}= 0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s$

Therefore, the speed of the resistive force is 42.426 m/s

8 0

3 years ago

HELP PLEASE <br> Find the net force necessary for a 15 kg object to accelerate at 20 m/s/s.

tensa zangetsu [6.8K]

Answer:

<h3>The answer is 300 N</h3>

Explanation:

The force acting on an object given the mass and acceleration we use the formula

<h3>force = mass × acceleration</h3>

We have

force = 15 × 20

We have the final answer as

Hope this helps you

3 0

3 years ago