Answer:
Star S has radial motion
Explanation:
Because the radial motion stracture is kinda similar to hydrogen spectrum(I'm guessing,only lol)
Explanation:
Given that,
Mass of disk = 1.2 kg
Radius = 0.07 m
Radius of rod = 0.11 m
Mass of small disk = 0.5 kg
Force = 29 N
Time t = 0.022 s

Distance d= 0.039 m
(I). We need to calculate the speed of the apparatus
Using work energy theorem



Where, m = total mass
v = velocity
F = force
d = distance
Put the value into the formula


(b). We need to calculate the angular speed of the apparatus
Using formula of torque





We need to calculate the angular speed of the apparatus
Using equation of angular motion

Put the value into the formula


(c). We need to calculate the angular speed of the apparatus
Using equation of angular motion

Put the value into the formula


Hence, This is required equation.
The wave takes 11.3 s to cover a distance of 26.5 m, so its speed is:

The distance between two consecutive crests is 3 m, and this corresponds to the wavelength of the wave. To find its frequency, we can use the relationship between the speed v, the wavelength

and the frequency f:
This is because most of the atom cannot move due to being held in place by surronding atoms, but electrons can move around and travel
<h2>
<em><u>⇒</u></em>Answer:</h2>
In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)
Step-by-Step Solution:
Solution 35PE
This question discusses about the increased range. So, we shall assume that the angle of jumping will be as the horizontal range is maximum at this angle.
Step 1 of 3<
/p>
The legs have an extension of 0.600 m in the crouch position.
So, m
The person is at rest initially, so the initial velocity will be zero.
The acceleration is m/s2
Acceleration m/s2
Let the final velocity be .
Step 2 of 3<
/p>
Substitute the above given values in the kinematic equation ,
m/s
Therefore, the final velocity or jumping speed is m/s
Explanation: