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Pirates drag a treasure chest to the left across a sandy beach. In which direction does the treasure chest experience a friction

yawa3891 [41]

Answer:

Chest experiences the friction forces towards right

Explanation:

Friction forces can be defined as a force a body experiences when it is made to slide against the surface. Friction force always acts to stop the the body which is moving. To stop the body, it always acts in the opposite directions to the motion of the body. Therefore, if the treasure chest is dragged across a sandy beach to the left, the frictional forces will act in the right direction.

5 0

3 years ago

1. In a certain semiconducting material the charge carriers each have a charge of 1.6 x 10-19 C. How many are entering the semic

Gennadij [26K]

Answer:

The number of charges is 1.25 × 10¹⁰

Explanation:

Current is the amount of charge flowing through a conductor per second. The formula for current (I) is given as:

I = Q/t

Where Q is the charge flowing in coulombs and t is the time taken in seconds.

Given that I = 2.0 nA = 2 × 10⁻⁹ A and t = 1 sec

I = Q / t

Q = It = 2 × 10⁻⁹ × 1 = 2 × 10⁻⁹ C

Since each charge = 1.6 x 10⁻¹⁹ C, therefore:

The number of charges = 2 × 10⁻⁹ C / 1.6 x 10⁻¹⁹ C = 1.25 × 10¹⁰

5 0

3 years ago

Which part of vernier caliper is used to measure internal diameter of cylinder

BlackZzzverrR [31]

Answer:

Circled in Red...plus the scales, of course.

Explanation:

6 0

3 years ago

A block pushed along the floor with velocity v0xv0x slides a distance dd after the pushing force is removed. If the mass of the

Volgvan

Answer:

There is no change in distance

Explanation:

Given that block slides a distance dd with initial velocity $v_{ox}$ $v_{ox}$

Work energy theorem states that Work done W is the difference between final kinetic energy $KE_{f}$ and initial kinetic energy $KE_{i}$

W = $KE_{f}$ - $KE_{i}$ ...........(equation 1)

In the given problem, the work is done by frictional force

Hence the work done is given by

$W_{Friction}$ = - $F_{Friction}$ x dd

$F_{Friction}$ is negative since it is resistive force and dd is the distance

$W_{Friction}$ = - μ mg X dd

where μ is coefficient of friction.

Also we know that Kinetic energy KE = $\frac{1}{2}$ $mv^{2}$

$KE_{f}$ = 0 since final velocity is zero

$KE_{i}$ = $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

Substituting the corresponding values equation 1 becomes

-μ mg x dd = 0 - $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

dd= $\frac{(v_{ox}v_{ox} )^{2} }{2g}$ x (1/μ) ........... (equation 2)

To find distance when mass of block is doubled and initial velocity is not changed:

Equation 2 shows that the distance dd is independent of mass, therefore there is no change in distance.

5 0

3 years ago

In an oscillating series RLCcircuit, with a 6.13 Ω resistor and a 15.2 H inductor, find the time required for the maximum energy

ivanzaharov [21]

Answer:

time for maximum energy is 1.718 sec

Explanation:

Maximum energy on the capacitor is given as $=\frac{q_{max}^2}{ 2C}$

Maximum energy $= \frac{(1/6) Q_2}{2C}$

The maximum charge is given by

$q_{max} =Qe^{-Rt/2L}$

Or $\frac{q_{max}}{Q} = e^{-Rt/2L}$

Or $ln\frac{q_{max}}{Q} = \frac{-Rt}{2L}$

solving for t

$t = \frac{2L}{R}\frac{1}{2} ln( 2)$

Putting all value to get desired value

$t = ln(2)\times \frac{L}{R}$

$t = 0.693\times \frac{(15.2}{6.13} = 1.71 sec$

8 0

3 years ago

I need help pls now ​plleeeeeeeeaaassseeeee

I need help pls now plleeeeeeeeaaassseeeee