Question

Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6 nm. What is the average surface temperature of Sigma rounded to the nearest whole number

Answer 1

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

$T=\frac{b}{\lambda}$

where

T is the surface temperature

b is Wien's displacement constant

$\lambda=2\cdot 10^{-6} m$

So the surface temperature of the star is

$T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K$

Answer 2

Answer:

1,450 K

Explanation: