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aev [14]
3 years ago
10

Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6

nm. What is the average surface temperature of Sigma rounded to the nearest whole number
Physics
2 answers:
puteri [66]3 years ago
8 0

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

T=\frac{b}{\lambda}

where

T is the surface temperature

b is Wien's displacement constant

\lambda=2\cdot 10^{-6} m

So the surface temperature of the star is

T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K

Kruka [31]3 years ago
7 0

Answer:

1,450 K

Explanation:

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