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3 years ago

10

Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6

nm. What is the average surface temperature of Sigma rounded to the nearest whole number

2 answers:

puteri [66]3 years ago

8 0

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

$T=\frac{b}{\lambda}$

where

T is the surface temperature

b is Wien's displacement constant

$\lambda=2\cdot 10^{-6} m$

So the surface temperature of the star is

$T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K$

Kruka [31]3 years ago

7 0

Answer:

1,450 K

Explanation:

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A gold nucleus is 466 fm (1 fm = 10-15 m) from a proton, which initially is at rest. When the proton is released, it speeds away

Artist 52 [7]

Answer:

$v=6.8\times10^6m/s$

Explanation:

The sum of the kinetic and electric potential energies of the proton when initially released must be equal to their sum at infinity, so we have:

$K_i+U_i=K_f+U_f$

Which, since $K_i=0J$ because initially the proton is at rest, is:

$\frac{kqQ}{d}=\frac{mv^2}{2}+\frac{kqQ}{r_\infty}$

where $k=9\times10^9Nm^2/C^2$ is Coulomb's constant, $q=1.6\times10^{-19}C$ the charge of the proton, $Q=(79)(1.6\times10^{-19})C$ the charge of the gold nucleus, since it has 79 protons, $d=466\times10^{-15}m$ the initial separation between them, $m=1.67\times10^{-27}kg$ the mass of the proton and v its final velocity. $r_\infty$ is very far away, so the final electric potential will be 0J, and we have:

$v=\sqrt{\frac{2kqQ}{md}}=\sqrt{\frac{2(9\times10^9)(1.6\times10^{-19})^2(79)}{(1.67\times10^{-27})(466\times10^{-15})}}m/s=6839409m/s$

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3 years ago

A car accelerates uniformly from rest at a speed of 1.67 ft s^2 over a distance of 5 yards.What is the acceleration of a car?

Nina [5.8K]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

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3 years ago

Read 2 more answers

Derive the dimension of Power

stellarik [79]

Answer:

The dimension of power is energy divided by the time or $[ML^2T^-3]$

Explanation:

Power = $\frac {Work Done}{Time}$

We can derive Dimensions of Power from both formula.

Power = Force * Velocity

As,

Force = mass * acceleration

Therefore, Dimensions of

Force = $[M]*[LT^-2] = [MLT^-2]$

Since,

Velocity = $\frac{Length}{Time}$

Now, Dimension of

Velocity = $[LT^-1]$

We have Both Dimensions,Now we can derive Dimensions Of Power,

Power = Force * Velocity

Power = $[MLT^-2] * [LT^-1]$

Power = $[ML^2T^-3]$

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What kinds of bonds are possible between carbon and oxygen?

ikadub [295]

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<em>Kinetic Energy</em>

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<em>Potential</em><em> </em><em>Energy</em><em> </em>

<u><em>=</em><em>></em><em>potential energy is the energy held by </em></u><em><u>an</u></em>

<em><u> object because of its position relative to </u></em><em><u>other</u></em>

<em><u> objects, stresses within itself, its </u></em><em><u>electric</u></em>

<em><u> charge, or other factors.</u></em>

<h2>Difference:</h2>

=>Potential energy is a <u>stored</u> energy on the other hand kinetic energy is the energy of an object or a system's particle in <em><u>Motion</u></em>.

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