25,000 Feet = 7620m
PE = mgh where m is mass, g is gravity accel: 9.8 n h is height
= 90 x 9.8 x 7620
= 6720840J
= 6.72MJ
F = ma where m is mass, a is accel = gravity = 9.8
= 90 x 9.8
= 882N
Accel = gravity = 9.8m/s^2
KE = 1/2mv^2 where m is mass n v is vel
if no wind resistance, PE leaving airplane = KE at net
6720840 = 1/2 x 90 x v^2
v^2 = 149352
v = 386.5m/s
The distance covered is 1000 m
Explanation:
The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

where
s is the distance covered
v is the final velocity
t is the time
a is the acceleration
For the rocket in this problem, we have:
v = 445 m/s is the final velocity
is the acceleration
t = 4.50 s is the time
Substituting, we find the distance covered:

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It allows people to see around the corner and anticipate what speed changes they will need to make
The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N
Data given;
- mass = 15kg
- angle = 30 degree
- acceleration = 1.2 m/s^2
- acceleration due to gravity = 9.8 m/s^2
<h3>Force against gravity</h3>
To move the plane upward, the box will move against gravity.

Let's solve for F

<h3>Force towards gravity</h3>
When the force pushes the box down the inclined plane, it moves towards gravity.

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N
Learn more on force across an inclined plane here;
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