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mel-nik [20]
4 years ago
12

Boyle's law says that the volume of a gas varies inversely with the pressure. when the volume of a certain gas is 5l, the pressu

re is 512 kpa(kilopascals). what is the pressure when the volume is 4l
Physics
1 answer:
Mrac [35]4 years ago
8 0
Boyle's law states:
pV = C, where p = pressure, V = volume, C = constant.

Therefore,
p1V1 = p2V2

And the,
p2 = p1V1/V2
p1 = 512 kPa
V1 = 5l
p2 =?
V2 = 4l

Therefore,
p2= 512*5/4 = 640 kPa
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98 POINTS, 5 simple questions!! HELP
lozanna [386]

25,000 Feet = 7620m

PE = mgh where m is mass, g is gravity accel: 9.8 n h is height

= 90 x 9.8 x 7620

= 6720840J

= 6.72MJ

F = ma where m is mass, a is accel = gravity = 9.8

= 90 x 9.8

= 882N

Accel = gravity = 9.8m/s^2

KE = 1/2mv^2 where m is mass n v is vel

if no wind resistance, PE leaving airplane = KE at net

6720840 = 1/2 x 90 x v^2

v^2 = 149352

v = 386.5m/s


3 0
3 years ago
Read 2 more answers
A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At
Pani-rosa [81]

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

Learn more about accelerated motion:

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8 0
4 years ago
Chance drives his scooter 7km north he stops for lunch and then drives 5km East to his friend house what distance did he cover
Katena32 [7]

Answer:12km

Explanation:

7km+5km=12km

6 0
3 years ago
How does putting a mirror on a sharp bend help to prevent accidents
timofeeve [1]
It allows people to see around the corner and anticipate what speed changes they will need to make
6 0
3 years ago
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An inclined plane makes an angle of 30.0º with the horizontal. 
Wittaler [7]

The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N

Data given;

  • mass = 15kg
  • angle = 30 degree
  • acceleration = 1.2 m/s^2
  • acceleration due to gravity = 9.8 m/s^2

<h3>Force against gravity</h3>

To move the plane upward, the box will move against gravity.

F = F - mgcos X\\&#10;ma = F - mg cosX

Let's solve for F

ma = F - mgcosX\\&#10;15*1.2 = F - 15*9.8 * cos 30\\&#10;18 = F - 127.30\\&#10;F = 18 + 127.30\\&#10;F = 145.3N

<h3>Force towards gravity</h3>

When the force pushes the box down the inclined plane, it moves towards gravity.

F = F + mgcosX\\&#10;ma = F + mgcosX\\&#10;15*1.2 = F + 15*9.8*cos30\\&#10;F = -109.3N

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N

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3 years ago
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