Question

A boat crosses a river of width 244 m in which the current has a uniform speed of 1.99 m/s. The pilot maintains a bearing (i.e., the direction in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 1.68 m/s relative to the water. How far downstream from the initial position is the boat when it reaches the opposite shore

Answer 1

Answer:289.02\ m

Explanation:

Given

width of river $d=244\ m$

velocity of current $v_1=1.99\ m/s$

Velocity of boat w.r.t to current $v_{21}=1.68\ m/s$ perpendicular to current

therefore Perpendicular component of velocity will help boat to cover the width of river in $t_1$ time which is given by

$t_1=\frac{244}{v_{21}}$

$t_1=\frac{244}{1.68}=145.23\ s$

In this time current will drift the boat a distance of

$x=v_1\times t_1$

$x=1.99\times 145.23$

$x=289.02\ m$