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andrew-mc [135]
3 years ago
5

A boat crosses a river of width 244 m in which the current has a uniform speed of 1.99 m/s. The pilot maintains a bearing (i.e.,

the direction in which the boat points) perpendicular to the river and a throttle setting to give a constant speed of 1.68 m/s relative to the water. How far downstream from the initial position is the boat when it reaches the opposite shore
Physics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:289.02\ m

Explanation:

Given

width of river d=244\ m

velocity of current v_1=1.99\ m/s

Velocity of boat w.r.t to current v_{21}=1.68\ m/s perpendicular to current

therefore Perpendicular component of velocity will help boat to cover the width of river in t_1 time which is given by

t_1=\frac{244}{v_{21}}

t_1=\frac{244}{1.68}=145.23\ s

In this time current will drift the boat a distance of

x=v_1\times t_1

x=1.99\times 145.23

x=289.02\ m  

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