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kolbaska11 [484]

2 years ago

12

An angle is observed repeatedly using the same equipment and procedures producing the data below:35 ∘ 40'00",35 ∘ 40'10",35 ∘ 40

'10", and 35 ∘ 39'55"A) Calculate the standard deviation.B)Calculate the standard deviation of the mean.

1 answer:

Helen [10]2 years ago

6 0

Answer: (a) +/- 7.5° (b) +/- 3.75°

Explanation:

See attachment

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Frequency = $3.5294\times 10^{14}s^{-1}$

Wavenumber = $1.1765\times 10^6m^{-1}$

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Energy = $2.3365\times 10^{-12}erg$

Explanation:

As we are given the wavelength = 850 nm

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The relation between frequency and wavelength is shown below as:

$Frequency=\frac{c}{Wavelength}$

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So, Frequency is:

$Frequency=\frac{3\times 10^8m/s}{850\times 10^{-9}m}$

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Wavenumber is the reciprocal of wavelength.

So,

$Wavenumber=\frac{1}{Wavelength}=\frac{1}{850\times 10^{-9}m}$

$Wavenumber=1.1765\times 10^6m^{-1}$

Also,

$Energy=h\times frequency$

where, h is Plank's constant having value as $6.62\times 10^{-34}J.s$

So,

$Energy=(6.62\times 10^{-34}J.s)\times (3.5294\times 10^{14}s^{-1})$

$Energy=2.3365\times 10^{-19}J$

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$1J=6.24\times 10^{18}eV$

So,

$Energy=(2.3365\times 10^{-19})\times (6.24\times 10^{18}eV)$

$Energy=1.4579eV$

Also,

$1J=10^7erg$

So,

$Energy=(2.3365\times 10^{-19})\times 10^7erg$

$Energy=2.3365\times 10^{-12}erg$

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