Answer:
Thrust
Explanation:
If the pilot wants to accelerate the aircraft, the aircraft needs more power to produce more thrust. The aircraft will go faster when the amount of thrust is greater than the amount of drag.
Answer:
X=0.194
T=-33.6C
Explanation:
Hello!
To solve this problem use the following steps!
1. We will call the expansion valve inlet 1 and exit 2
2.Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
3. Find the enthalpy of state 1 using pressure and temperature using thermodynamic tables
h1=Enthalpy(Ammonia;T=24C;P=1000kPa)=312.9KJ/kg
4. An expansion valve is a device which does not have heat or work exchange which means that the enthalpy of state one is equal to that of state 2, so using thermodynamic tables uses the pressure of state 2 and enthalpy of state 1 to find quality and temperature
x2=Quality(Ammonia;P=100kPa;h=h1=312.9KJ/kg)
=0.194
T2=Temperature(Ammonia;P=100kPa;h=h1=312.9KJ/kg)=-33.6C
Answer:
Companies are combining their online business activities with their existing physical presence in order to lower costs of their operations. When both these things are combined labor costs are reduced because with online presence the company has to have limited number of branches, inventory costs are reduced because additional inventories for every physical outlet is not required and delivery costs are reduced because now company don't have to supply the things to all the outlets on regular basis.
Trust of the people is also improved because mostly people are reluctant to order from the brands that only have their online store and donot have any physical presence. Value added services are provided by a company who have both online and offline presence like home delivery and customized offerings.
Answer:
clear, clc
prob3_5([1,2,3],[6,5,7],12,11,22,55,76)
function T=prob3_5(x,y,N,L,W,T1,T2)
w=zeros(1,length(x));
for n=1:2:N
for i=1:length(x)
w(i)=w(i)+(2/pi)*(2/n)*sin(n*pi*x(i)/L).*sinh(n*pi*y(i)/L)/sinh(n*pi*W/L);
end
end
T=(T2-T1)*w+T1;
end
Explanation:
Please input the commands into MATLAB
