A woman places her briefcase on the backseat of her car. As she drives to work, the car negotiates an unbanked curve in the road
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Answer:
(a). The speed of the first ball after the collision is 1.95 m/s.
(b). The direction of the first ball after the collision is 44.16° due south of east.
Explanation:
Given that,
Velocity of one ball u₁= 2.2i m/s
Velocity of second ball u₂=- 0.80i m/s
Final velocity of the second ball v₂= 1.36j m/s
The mass of the identical balls are
(a). We need to calculate the speed of the first ball after the collision
Using law of conservation of momentum
Along X- axis
Put the value into the formula
Along Y-axis
Put the value into the formula
Then the final speed of the first ball
(b) We need to calculate the direction of the first ball after the collision
Using formula of direction
Negative sign shows the direction of first ball .
Hence, (a). The speed of the first ball after the collision is 1.95 m/s.
(b). The direction of the first ball after the collision is 44.16° due south of east.
Explanation:
The given data is as follows.
Spring constant (k) = 78 N/m,
Mass of block (m) = 0.50 kg
According to the formula of energy conservation,
mgh sin
h =
=
= 0.64 m
Thus, we can conclude that the distance traveled by the block is 0.64 m.