Answer:

Given:
Radius of ball bearing (r) = 1.5 mm = 0.15 cm
Density of iron (ρ) = 7.85 g/cm³
Density of glycerine (σ) = 1.25 g/cm³
Terminal velocity (v) = 2.25 cm/s
Acceleration due to gravity (g) = 980.6 cm/s²
To Find:
Viscosity of glycerine (
)
Explanation:


Substituting values of r, ρ, σ, v & g in the equation:






Answer:
<em>1,378.9ms²</em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms²</em>
Answer:
It has been learned in this lesson that the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period. ... Once calculated, this area represents the displacement of the object.
Explanation:
Mark Brainliest please
Answer : if connected series, 20 ohms
And if connected parallel, answer will be less than 20 ohms
When resistors are wired in series, the total circuit resistance increases because each resistor contributes opposition to the circuit's current flow. Therefore if a 10 ohm resistor is placed in series with another 10 ohm resistor, the total resistance contributed by the two resistors is 20 ohms.
Answer:
the final speed of object A changed by a factor of
= 0.58
the final speed of object B changed by a factor of
= 1.29
Explanation:
Given;
kinetic energy of object A, = 27 J
let the mass of object A = 
then, the mass of object B = 
work done on object A = -18 J
work done on object B = -18 J
let
be the initial speed
let
be the final speed
For object A;


Thus, the final speed of object A changed by a factor of
= 0.58
To obtain the change in the final speed of object B, apply the following equations.


Thus, the final speed of object B changed by a factor of
= 1.29