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3 years ago

Match the descriptions of motion in the first column to the displacement versus time graphs in the second column.

Physics

1 answer:

pickupchik [31]3 years ago

4 0

For the description steadily increasing displacement, constant positive velocity, the graph would be the second one. As time increases, the displacement as well increases steadily.

For steadily decreasing displacement, the first one would be the most suitable. As time increases, the displacement decreases on a steady manner.

For the third description, the graph would be close to the fourth one. Since as the time increases, the distance increases but the increase depends from point to point

For the fourth description, the correct graph is the third one. The distance is constant throughout the duration of the motion.

Lastly, the last description would match to the last graph where displacement is increasing however the velocity gradually decreases.

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A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bo

drek231 [11]

Answer:

$T = 37.5 N$

Explanation:

As the pendulum reached to the lowest position then we will have

$T - mg = \frac{mv^2}{L}$

$14.2 - m(9.81) = \frac{m(2.9^2)}{L}$

now when it will reach to the height of the peg then its speed is given as

$v_f^2 - v_i^2 = 2 a d$

so we will have

$v_f^2 - 2.9^2 = 2(-9.81)(\frac{L}{5})$

$v_f^2 = 2.9^2 - 3.924L$

also we know that

$2.9^2 - 0 = 2(9.81)(L)$

$L = 0.43 m$

$m = 0.48 kg$

now we have speed of the pendulum when it reach the same height is given as

$v_f^2 = 2.9^2 - (3.924(0.43)$

$v_f = 2.6 m/s$

Now the tension in the string is given as

$T = \frac{mv_f^2}{\frac{L}{5}}$

$T = \frac{0.48(2.6)^2}{\frac{0.43}{5}}$

$T = 37.5 N$

6 0

4 years ago

Why is it necessary that all three thermometers were at approximately the same distance from the light bulb

iris [78.8K]

I'm assuming it was to keep the data consistent? The further you are from a heat source the less heat will get to you as the temperature tries to reach equilibrium and the waves start to spread out, so you should keep everything the same distance to get consistent results. I don't have any information so this is just my assumption

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4 years ago

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Soloha48 [4]

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$F=\frac{GMm}{r^{2}}$

Thus, The force of gravitation is inversely proportional to the distance.

Kepler's law states that the square of period of planet is proportional to cube of semi major axis of its orbit.

The time period of planet is more when the gravitational force is less.

Thus, planet Y is closer to earth because sun exert greater gravitational force than planet Z.

8 0

4 years ago

Read 2 more answers

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0

IceJOKER [234]

Answer:

Explanation:

This is a case of interference of sound , akin to YDSE in optics .

Here, like interference dark and bright fringes, region of silence and intense sound will be formed due to destructive and constructive interference respectively.

Here d = distance between two sources = 5 m

D = distance of source and screen = 12m

position of first destructive interference

= λ D /2d

1 = λ 12 /2x 5

λ = 5 / 6 m

frequency = v / λ

= 343 x 6/ 5

= 411.6 Hz

7 0

3 years ago

A plane is flying with an airspeed of 190 miles per hour and heading 150°. The wind currents are running at 30 miles per hour at