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2 years ago

Who is Carl Jung???????

Physics

2 answers:

mina [271]2 years ago

8 0

Answer:

Carl Gustav Jung was a Swiss psychiatrist , founder of analytical psychology . His work has been and remains influential in the fields of psychiatry , psychology , religious science , literature and related fields .

Ierofanga [76]2 years ago

7 0

Answer: Carl Gustav Jung was a Swiss psychiatrist and psychoanalyst who founded analytical psychology. Jung's work has been influential in the fields of psychiatry, anthropology, archaeology, literature, philosophy, psychology, and religious studies.

Explanation:

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Graph the following data on the graph, then use the graph to determine the half-life of this isotope.

Harlamova29_29 [7]

Answer:

4, 56

Explanation:

Hope this helped!

7 0

3 years ago

A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The

mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

$v = v_{o}+a\cdot t$

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t$ - Time, measured in seconds.

Now, we clear acceleration within expression:

$a = \frac{v-v_{o}}{t}$

Initial and final velocities are now converted from kilometers per hour into meters per second:

$v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v_{o} = 30\,\frac{m}{s}$

$v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v = 37.5\,\frac{m}{s}$

If we know that $t = 3.5\,s$ , then, the average acceleration of the car is:

$a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}$

$a = 2.143\,\frac{m}{s^{2}}$

The average acceleration of the car is 2.143 meters per square second.

8 0

3 years ago

Calculate the average speed in metres per second from Glasgow to Ediburgh ( The table )

Angelina_Jolie [31]

Total distance is 28+12+34=74km=74000m.
Total time is 20+8+25 minutes=53 minutes=53×60=3180 secs.
Average speed is 74000/3180=23.27 m/s.

7 0

3 years ago

A landscaper is making a retaining wall to shore up the side of a hill. to ensure against collapse, the wall should make an angl

Musya8 [376]

Refer to the diagram shown below.

Let x = distance of the base of the ladder from the base of the hill.

By definition,
sin(75°) = x/15
x = 75*cos(75°) = 3.882 ft

Answer:
The distance between the base of the hill and the base of the ladder is 3.9 ft (nearest tenth)

3 0

4 years ago

An alternator consists of a coil of area A with N turns that rotates in a uniform field B around a diameter perpendicular to the

matrenka [14]

Answer:

(a): $\rm 2\pi f\ NBA\ \sin(2\pi ft).$ .

(b): 20.94 Volts.

Explanation:

<u>Given:</u>

Area of the coil = A.
Number of turns of the coil = N.
Magnetic field in which the coil is placed = B.
The frequency with which the coil is rotating = f.

The magnetic flux linked with a coil is defined as

$\phi = N\vec B \cdot \vec A=\rm NBA\cos\theta$

where,

$\vec A$ is the area vector of the coil, directed along the normal to the plane of the coil.

$\theta$ = angle between the magnetic field and the area vector of the coil.

Assuming that the magnetic field is along the normal to the plane of the coil, initially.

Therefore, at any later time t, the angle which the magnetic field makes with the normal to the plane of the coil is is given by

$\rm \theta = 2\pi ft.$

Therefore, the magnetic flux linked with the coil at any time t is given by

$\rm \phi = NBA\cos(2\pi ft).$

According to the Faraday's law of electromagnetic induction, the emf induced in the coil is given by

$\rm e=-\dfrac{d\phi}{dt}\\=-\dfrac{d(NBA\cos(2\pi ft))}{dt}\\=-NBA\dfrac{d(\cos(2\pi ft))}{dt}\\=-NBA(-2\pi f\sin(2\pi ft))\\=2\pi f\ NBA\ \sin(2\pi ft).$

The amplitude of the alternating voltage is the maximum value of the induced emf in the coil, the induced emf in the coil is maximum when $\rm \sin(2\pi ft)=1$ .

Therefore, the amplitude of the alternating voltage is given by

$\rm e_o=(2\pi f)NBA\ 1\\=2\pi ft \ NBA.$

Given values are:

N = 100 turns.
A = $\rm 10^{-2}\ m^2$ .
B = 0.1 T.
f = 2000 rev/min = $\rm 2000\times \dfrac1{60}\ rev/s = 33.33\ rev/s.$

Putting all these values,

$\rm e_o=2\pi \times 33.33\times (100)\times (0.1)\times (10^{-2})=20.94\ Volts.$

7 0

3 years ago