Select all that apply.

1) the diagonal force times the sine of the angle it makes will give you the vertical component or y component . use this to get the vertical components of all the diagonal forces . add all the vertical components as well as the vertical forces together

2) the diagonal force times the cosine of the angle it makes gives the horizontal component or x component. do this to get the x component of all the diagonal forces.

add all the x components as well as the horizontal forces together to get the final x component

3)using the triangle of vectors, the resultant force is calculated

sum of y component = 3.2N

sum of x component= 5.7N

resultant force = 6.5N

3 0

3 years ago

Tarzan is in the path of a pack of stampeding elephants when Jane swings in to the rescue on a rope vine, hauling him off to saf

timurjin [86]

Answer:

h = 3.56 m

Explanation:

Assuming no friction on the rope or air resistance, we can apply the conservation of mechanical energy principle to the first part of the trajectory, from when Jane starts her swing till she catches Tarzan at the ground level.

⇒ $\Delta K + \Delta U = 0 (1)$

Rearranging terms, we get:

$U_{ij} + K_{ij} = U_{fj} + K_{f} (2)$

Now, as Jane starts from rest, Kij =0.
if we choose the ground level as our zero reference level, it will be also Ufj = 0.
Replacing in (2) by the expressions of Uij and Kfj, we have:

$m_{j} * g* h_{ij} = \frac{1}{2} * m_{j} * v_{fj} ^{2} (3)$

Replacing in (3) by the givens, and rearranging terms, we can solve for vfj, as follows:

$v_{fj} =\sqrt{2*9.8 m/s2*27 m} = 23 m/s (4)$

Now, as once jane catches Tarzan, both continue swinging together, we can take the catching moment as a completely inelastic collision.
Assuming no external forces act during the collision, total momentum must be conserved.

⇒ $p_{o} = p_{f} (5)$

Assuming that Tarzan is at rest when Jane catches him, the initial momentum will be simply as follows:

$p_{o} = m_{j} * v_{j} = 49 kg * 23 m/s = 1127 kg*m/s (6)$

The final momentum, will be just the product of the combined mass of Jane and Tarzan times the common speed for them after the collision:

$p_{f} = (m_{j} + m_{t} ) * v_{jt} = 135 kg* v_{jt} (7)$

As (6) and (7) are equal each other, we can solve for vjt, as follows:

$v_{jt} = \frac{1127 kg*m/s}{135 kg} = 8.35 m/s (8)$

Finally we can apply the same energy conservation principle to the last part of the trajectory, as follows:

$U_{ijt} + K_{ijt} = U_{fjt} + K_{fjt} (9)$

We know that Uijt = 0 and also that Kfjt = 0, due to both starts from the ground level and reach to the highest point before starting to fall down, so at this point, the kinetic energy will be zero.
Replacing by the givens and the result from (8), we can solve for the h as follows:
$h_{f} =\frac{v_{ijt} ^{2} }{2*g} = \frac{69.7m2/s2}{2*9.8m/s2} = 3.56 m$

8 0

3 years ago

Technician A says a special puller and installer tool is required to remove and install the vibration damper. Technician B says

andrey2020 [161]

Answer:

Both of them are correct

Explanation:

Here both the technician are correct. A special puller and installer tool is required to remove and install the vibration damper. Removing and installing a damper is not an easy task, it requires a definite set of technique and tools.

According to Technician B if the inertia ring on the vibration damper is loose, the damper must be replaced is absolutely correct, inertia ring once loosened cannot be tightened. hence, we have change the the damper.

6 0

3 years ago