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aleksandr82 [10.1K]
2 years ago
10

What effects does the conductor have on the potential field?

Physics
1 answer:
liraira [26]2 years ago
8 0
Type of conductors determines rate of flow of current
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A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig
vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

CPR=\frac{KW}{DAT}

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6  to give CPR in mm/yr

mpy

CPR=\frac{KW}{DAT}

        =\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}

        =37.4mpy

mm/yr

CPR=\frac{KW}{DAT}

        =\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}

       =0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0
3 years ago
Why were the rings of Uranus not observed directly from telescopes on the ground on Earth? How were they discovered?
leonid [27]

Answer:Explained below.

Explanation:

Uranus rings is made up of jet black, coal-like particles in small bands, making them difficult  to perceive from Earth.This indicates that they are probably composed of a mixture of the ice and a dark material. The nature of  material is dismal, but it might be some organic compounds greatly darkened by the charged particle irradiation from the Uranian magnetosphere. Rings were discovered by using a infrared telescope throughout  the occultation of a star as Uranus passed in front of it. The light from the star dimmed many times before it was obstructed by the disk of Uranus and subsequently, showing the presence of various distinct rings.

6 0
3 years ago
A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial s
Verdich [7]

<span>(1)   </span>Through the Second Law of motion, the equation  for Force is:

                                 F = m x a

Where m is mass and a is acceleration (deceleration)

 

<span>(2)   </span>Distance is calculated through the equation,

                             D = Vi^2 / 2a

Where Vi is initial velocity

<span>(3)   </span>Work is calculated through the equation,

                          W = F x D

 

Substituting the known values,

Part A:

<span>(1)   </span>  F = (85 kg)(2 m/s^2) = 170 N

<span>(2)   </span>  D = (37 m/s)^2 / (2)(2 m/s^2)  = 9.25 m

<span>(3)   </span>  W = (170 N)(9.25 m) = 1572.5 J

 

Part B:

<span>(1)   </span> F = (85 kg)(4 m/s^2) = 340 N

<span>(2)   </span>D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

<span>(3)   </span><span> W = (340 N)(4.625 m) = 1572.5 J</span>

7 0
3 years ago
Question: Which one of the following foods contains simple carbohydrates?
Katena32 [7]

Answer:

Milk

Hope this helps,if not sorry

5 0
3 years ago
sound of thunder is heard 5s after the flash of lighting is seen. calculate the distance of nearest point of lighting if the spe
Karolina [17]

Answer:

formula

speed = distance / time

distance = speed x time

distance = 346 x 5

distance = 1730 m

The distance of the lightening strike would be 1730 m or 1.7 km

Explanation:

6 0
3 years ago
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