Answer:
Number of mole in H2O = 5.4 moles
Explanation:
Given:
Mass of H2O = 97.3 gram
Find:
Number of mole in H2O
Computation:
We know that molar mass of H2O = 18 g/mole
So,
Number of mole = Given Mass / Molar mass
Number of mole in H2O = Mass of H2O / Molar mass of H2O
Number of mole in H2O = 97.3 / 18
Number of mole in H2O = 5.4055
Number of mole in H2O = 5.4 moles
Rubidium because it is lower on the periodic table and therefore has more electrons to shield the valence electrons from the positive core
Answer:
0.0102moles CaCl₂.2H₂O
0.0102moles CaCl₂
Explanation:
To convert moles to grams or vice versa of a compound, it is necessary to find molar mass of this substance.
For the CaCl₂.2H₂O:
This is the calcium chloride dihydrate (Because there are 2 molecules of water). That means you have 1 atom of Ca, 2 atoms of Cl, 4 atoms of H and 2 atoms of C. <em>Molar mass is the algebraic sum of the atomic weights that compose the molecule. </em>
Molar mass:
Ca: 1ₓ40.08g/mol = 40.08g/mol
Cl: 2ₓ35.45g/mol = 70.90g/mol
H: 4ₓ1.01g/mol: 4.04g/mol
O: 2ₓ16g/mol: 32g/mol.
40.08 + 70.90 + 4.04 + 32 = <em>147.02g/mol</em>
By using the molar mass of the susbtance, 1.50g are:
1.50g ₓ (1mol / 147.02g) =
<h3>0.0102moles CaCl₂.2H₂O</h3>
In the 1.50g of CaCl₂.2H₂O you have 0.0102 moles. As you can see, 1 mole of the dihydrate substance contains 1 mole of CaCl₂. Thus, you have:
<h3>0.0102moles CaCl₂</h3><h3 />
Answer:
15.5 km
Explanation:
1.55x10^4m
1.55x10000m
15500m
1km=1000m
b=15500m
1km*15500m=b*1000m
1km*15500m/1000m=b*1000m/1000m
b=15.5km
Hope this helps ;) ❤❤❤
Answer : The correction equation will be:
![Cs^+(g)+1e^-\rightarrow Cs(g)](https://tex.z-dn.net/?f=Cs%5E%2B%28g%29%2B1e%5E-%5Crightarrow%20Cs%28g%29)
Explanation :
Electron affinity : It is defined as the addition of electron to the atom or to the ion. The atom or ion is always in gaseous phase.
In other words we can say that, the gaining of electrons is said to be an electron affinity.
As, the given element is a metal given in cationic form, so its positive ion will gain an electron to form a neutral atom.
The balanced and correct equation for electron affinity of the cesium ion will be:
![Cs^+(g)+1e^-\rightarrow Cs(g)](https://tex.z-dn.net/?f=Cs%5E%2B%28g%29%2B1e%5E-%5Crightarrow%20Cs%28g%29)