Answer:
The relative rates of diffusion for methane and oxygen is 1.4142.
Methane gas will be able to travel 1.4142 meter in the same conditions.
Explanation:
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:
We are given:
Molar mass of methane gas, m = 16 g/mol
Molar mass of oxygen gas,m' = 32 g/mol
By taking their ratio, we get:
The relative rates of diffusion for methane and oxygen is 1.4142.
If oxygen gas travels 1 meters in time t.
Rate of diffusion of oxygen =
If methane gas travels travels in y meters in time t.
Rate of diffusion of methane=
y = 1.4142 m
Methane gas will be able to travel 1.4142 meter in the same conditions.
Answer:
Option A
They are located near the equator
Explanation:
From the diagram, we can observe that all the rain forest zones occur near the equator.
This is because on an annual basis, the equator receives the highest concentration of solar radiation in the whole Earth. This implies that the rate of evaporation of water from the water bodies present is high, and consequently, the amount of rainfall is high also. This abundant sunshine and high rainfall leads to the growth of the tropical rain forests at those regions
Answer:
Explanation:
We want to convert from moles to grams, so we must use the molar mass.
<h3>1. Molar Mass</h3>
The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.
- Phosphorus (P): 30.973762 g/mol
- Iodine (I): 126.9045 g/mol
Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.
- I₃: 126.9045 * 3=380.7135 g/mol
- PI₃: 30.973762 + 380.7135 = 411.687262 g/mol
<h3>2. Convert Moles to Grams</h3>
Use the molar mass as a ratio.
We want to convert 3.14 moles to grams, so we multiply by that value.
The units of moles of PI₃ cancel.
<h3>3. Round</h3>
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.
The 2 in the ones place tells us to leave the 9.
3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation:
