Answer:the maximum Hall voltage across the strip= 0.00168 V.
Explanation:
The Hall Voltage is calculated using
Vh= B x v x w
Where
B is the magnitude of the magnetic field, 5.6 T
v is the speed/ velocity of the strip, = 25 cm/s to m/s becomes 25/100=0.25m/s
and w is the width of the strip= 1.2 mm to meters becomes 1.2 mm /1000= 0.0012m
Solving
Vh= 5.6T x 0.25m/s x 0.0012m
=0.00168T.m²/s
=0.00168Wb/s
=0.00168V
Therefore, the maximum Hall voltage across the strip=0.00168V
Answer: P = 36.75W
The additional power needed to account for the loss is 36.75W.
Explanation:
Given;
Mass of the runner m= 60 kg
Height of the centre of gravity h= 0.5m
Acceleration due to gravity g= 9.8m/s
The potential energy of the body for each step is;
P.E = mgh
P.E = 60 × 9.8 × 0.5
PE = 294J
Since the average loss per compression on the leg is 10%.
Energy loss = 10% (P.E)
E = 10% of 294J
E = 29.4J
To calculate the runner's additional power
given that time per stride is = 0.8s
Power P = Energy/time
P = E/t
P = 29.4J/0.8s
P = 36.75W
Answer:
Explanation:
Speed given = 125 m /min
125 /60 m /s
In 450 second it will travel
= 450 x 125 / 60
=937.5 m.
As the distance is covered in less than 450 seconds , The distance must be less than 937.5 m
In 400 seconds , it will travel
= 400 x 125 / 60
833.33 m
Since the distance is covered in more than 400 seconds , the distance must be more than ie 833.33 .
Hence the distance covered is more than .833 m but less than 937.5
In either case these distance are more than .8 km .
The middle or centre of the Earth is the core. However the middle of the layers from the surface to the centre of the Earth is known as mantle.
