Answer:
5.00 grams of salt contain more particles than 5.0 grams of sugar
Explanation:
Salt = NaCl
Molar mass = 58.45 g/mol
Sugar = C₁₂H₂₂O₁₁
Molar mass = 342.3 g/mol
Sugar's molar mass is higher than salt.
So 1 mol of sugar weighs more than 1 mol of salt
But 5 grams of salt occupies more mole than 5 grams of sugar
5 grams of salt = 5g / 58.45 g/m = 0.085 moles
5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles
In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.
Answer:
pH = 12.15
Explanation:
To determine the pH of the HCl and KOH mixture, we need to know that the reaction is a neutralization type.
HCl + KOH → H₂O + KCl
We need to determine the moles of each compound
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
The base is in excess, so the HCl will completely react and we would produce the same mmoles of KCl
HCl + KOH → H₂O + KCl
3 m 4 m -
1 m 3 m
As the KCl is a neutral salt, it does not have any effect on the pH, so the pH will be affected, by the strong base.
1 mmol of KOH has 1 mmol of OH⁻, so the [OH⁻] will be 1 mmol / Tot volume
[OH⁻] 1 mmol / 70 mL = 0.014285 M
- log [OH⁻] = 1.85 → pH = 14 - pOH → 14 - 1.85 = 12.15
Answer:
- metal sulfate
- metal sulfate
- copper sulfate
- copper nitrate
- copper chloride
- copper phosphate
- hydrochloric acid, water
- Potassium, sulfuric acid, water
(Correct me if I am wrong)
Both. Every nucleotide has a sugar, a nitrogenous base, and a phosphate group
It will received an H+. I’m not sure if that answers your question correctly
