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Alina [70]
3 years ago
10

What I said the molarity of an hcl solution if 24.0 ml is completely neutralized by 98.0 ml of 0.250m ca(oh)2

Chemistry
1 answer:
ozzi3 years ago
6 0
If molarity is in mol/dm3 
2HCL+Ca(OH)2=CaCl2+2H2O
Moles of ca(oh)2 = 98/1000 x 0.250
                           = 0.0245 moles
moles of hcl = 0.049 As the 1 is to 2 ratio among them
moles = molarity x volume 
0.049 = molarity x 24/1000
molarity=2.042 mol/dm3 
ANSWER IS 2.042 mol/dm3
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Answer:

Explanation:

From the given information:

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The I.C.E table can be represented as:

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Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

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K_c = (0.8325)^{1/2}

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3 years ago
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