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Alina [70]
4 years ago
10

What I said the molarity of an hcl solution if 24.0 ml is completely neutralized by 98.0 ml of 0.250m ca(oh)2

Chemistry
1 answer:
ozzi4 years ago
6 0
If molarity is in mol/dm3 
2HCL+Ca(OH)2=CaCl2+2H2O
Moles of ca(oh)2 = 98/1000 x 0.250
                           = 0.0245 moles
moles of hcl = 0.049 As the 1 is to 2 ratio among them
moles = molarity x volume 
0.049 = molarity x 24/1000
molarity=2.042 mol/dm3 
ANSWER IS 2.042 mol/dm3
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If you have a gold brick that is 2cm by 3cm by 4cm and has density of 19.3g/cm3, what is its mass?
natulia [17]
Volume = a x a x a  

V = 2 cm x 3 cm x 4 cm => 24 cm³

Density = 19.3 g/cm³

Mass = ?

Therefore:

m = D x V

m = 19.3 x 24

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4 0
3 years ago
1.00176 x 103<br> Scientific notation
Ber [7]

Answer:

1.0318128 × 10^2

Explanation:

7 0
3 years ago
Please help very urgent! &lt;3
LuckyWell [14K]

Answer:

a) Neutralisation

b) Combustion

c) Synthesis

d) Decomposition

e) Neutralisation

f) Double Displacement Reaction

h) Single Displacement Reaction

i) Double Displacement Reaction

j) Combustion

Explanation:

Synthesis  is a reaction where various compounds/ elements react to form a totally new compound.

Decomposition is a reaction where a single compound breaks down into several components due to excessive heating or energy applied.

Single Displacement Reaction is a type of chemical reaction where an element reacts with a compound and takes the place of another element in that compound.

Double Displacement Reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

Combustion is a reaction where a compound/ element oxidises in the presence of Oxygen.

Neutralisation reaction is a reaction where an acid reacts with a base to form a salt.

5 0
3 years ago
A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is c
Zarrin [17]

Answer:

C_{alloy}=0.497\frac{J}{g\°C}

Explanation:

Hello there!

In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:

Q_{allow}=-(Q_{water}+Q_{Al})

Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:

m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})

Then, we solve for specific heat of the metallic alloy to obtain:

C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}

Thereby, we plug in the given data to obtain:

C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}

Regards!

3 0
3 years ago
Which processes of the water cycle involve the movement of water in the liquid state?
dangina [55]

Answer:

Surface runoff and condensation

Explanation:

Let's define each of the given processes in order to understand them better:

  • evaporation is a process in which liquid phase transforms into a gas phase;
  • precipitation is a process in which we produce a solid phase, usually this is the case when we precipitate a salt out of a solution, analogy of precipitation for water would be transformation from a liquid to a solid phase, such as freezing;
  • surface runoff is a process in which water flows over the surface of a land without any change in its phase;
  • condensation is a process in which a gas transforms into a liquid.

All in all, notice that surface runoff keeps water in its liquid state, while all the other three options consider phase change. The only phase change of interest is condensation: we produce liquid water from water vapor and then we can analyze its movement in the liquid state.

6 0
3 years ago
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