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andrew11 [14]
3 years ago
15

State whether each of the following would increase, decrease, or leave the initial pH unchanged and explain your reasoning: Usin

g the same weak acid, but having a higher concentration. Decrease the initial pH because having a higher concentration of weak acid is the same as adding more H+ into a solution which means there is more acid being added into a solution and because of this it will decrease the pH of a solution. Using 80.00 mL of this weak acid instead of 40.00 mL. Will not change the initial pH because having a greater volume of weak acid will not affect the concentration of weak acid (H+ ions). Using a different weak acid that has a larger Ka value. Increase the initial pH because the larger the Ka value the more concentration to dissociate into H+.
Chemistry
1 answer:
fgiga [73]3 years ago
5 0

Answer:

1. Decrease the pH

2. The pH remains unchanged

3. Decrease the pH

Explanation:

We can calculate the pH of a weak acid using the following expression:

pH=-log [H^{+} ]=-log\sqrt{Ka \times Ca }   [1]

where,

Ka is the acid dissociation constant

Ca is the initial concentration of the acid

<em>State whether each of the following would increase, decrease, or leave the initial pH unchanged and explain your reasoning</em>

  1. <em>Using the same weak acid, but having a higher concentration. </em>According to eq. [1], a higher Ca leads to a higher [H⁺] and a lower pH.
  2. <em>Using 80.00 mL of this weak acid instead of 40.00 mL.</em> pH refers to a concentration, which is an intensive property, so it does not change when we change the amount of matter.
  3. <em>Using a different weak acid that has a larger Ka value.</em> According to eq. [1], a higher Ka leads to a higher [H⁺] and a lower pH.
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Draw the structure for cis-2,3-dibromo-2-hexene.
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First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:

      CH3 - CH = CH2 - CH2 - CH2 - CH3

Secong, put one Br on the second carbon and one Br on the third carbon:

    CH3 - CBr = CBr - CH2 - CH2 - CH3

Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


      H   Br          H     H      H
       |    |             |       |       |
H - C - C = C -  C  -  C  -  C - H
       |           |      |       |       |
      H          Br   H     H      H

The important fact to realize is that the two Br are in opposed sides of the molecule.
4 0
4 years ago
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A reaction is started with both reactants and products and proceeds in the reverse direction to reach equilibrium. Which of the
nekit [7.7K]

Answer:

Option A

Explanation:

A) Yes. The reaction reaches equilibrium when the rate of reaction of the reverse reaction is equal to the rate of the forward reaction , then the only cause for the reverse reaction to be favoured is that the initial rate of the reverse was greater than the forward one.

B) No. The rate constant of the reverse reaction can be greater than the forward one  but the rate also depends on concentrations, thus a reverse reaction with greater rate constant can result in the net reaction proceeding in the forward reaction, the reverse reaction or be at equilibrium depending on the concentrations or reactants and products

C) No. A lower activation energy means a higher rate constant , but a higher rate constant does not mean that the net reaction will proceed to the reactants ( see point B)

D) No. The energy changes determine conditions under thermodynamic equilibrium and therefore the net direction of the reaction will depend on the temperature and concentrations of reactants and products with respect to the equilibrium conditions.

6 0
3 years ago
A drop of water with a mass of 0.48 g is vaporized at 100 ∘C and condenses on the surface of a 55- g block of aluminum that is i
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The final temperature in Celsius of the metal block is 49°C.

<h3>How to find the number of moles ?</h3>

Moles water = \frac{\text{Given mass}}{\text{Molar Mass}}

                     = \frac{0.48\ g}{18\ \text{g/mol}}

                     = 0.0266 moles  

                   

Heat lost by water = 0.0266 mol x 44.0 kJ/mol

                                = 1.17 kJ

                                = 1170 J           [1 kJ = 1000 J]

Heat lost = Heat gained

Heat gained by aluminum = 1170 J  

1170 = 55 x 0.903 (T - 25) = 49.7 T - 1242  

1170 + 1242 = 49.7 T  

T = 48.5°C (49°C at two significant figures)

Thus from the above conclusion we can say that The final temperature in Celsius of the metal block is 49°C.

Learn more about the Moles here: brainly.com/question/15356425

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7 0
2 years ago
A cylinder containing carbon dioxide of volume 20 L at 2.0 atm was connected to another cylinder of certain volume at constant t
den301095 [7]

Answer:

The volume of the second cylinder is 80 liters

Explanation:

We use the Boyle-Mariotte formula, according to which the pressure and volume of a gas are inversely related, keeping the temperature constant: P1 x V1 = P2xV2. We convert the pressure in mmHg to atm:

760 mmHg-----1 atm

380mmHg------x= (380mmHgx1atm)/760mmHg=0,5 atm

P1xV1=P2xV2

2 atmx20 L= 0,5atm x V2 V2=(2 atmx20 L)/0,5atm=80L

8 0
3 years ago
How much heat is required to raise the temperature of a 6.21 g sample of iron from 25.0 oC to 79.8 oC?
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Answer:

151.1J

Explanation:

Given parameters:

Mass of iron  = 6.21g

Initial temperature of iron  = 25°C

Final temperature of iron  = 79.8°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat require to cause this temperature can be determined using the expression below;

    H  = m c (T₂ - T₁)

H is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature

    Specific heat capacity of iron 0.444J/g°C

Insert the parameters and solve;

     H  = 6.21 x 0.444 x (79.8 - 25)

     H   = 151.1J

5 0
3 years ago
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