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Marina CMI [18]
3 years ago
14

Calculate the density of a liquid if 58.9 ml of it has a mass of 46.08 g. answer in units of g/ml.

Chemistry
1 answer:
alexira [117]3 years ago
8 0
Density of a solution is mass of solution per unit volume
Density = mass/volume
mass of solution is 46.08 g
volume of solution is 58.9 mL 
since mass and volume is known, density can be calculated
density = 46.08 g / 58.9 mL = 0.78 g/mL 
You might be interested in
The angular momentum quantum number (l) value of 0 indicates the ________ subshell.
bonufazy [111]

Answer:

indicates the number of subshells

4 0
3 years ago
Citric acid is often used as an acidity regulator in hot water canning of tomatoes. At 25°C it has Kat 7.4x10- and A.Hº = +4.1 k
gavmur [86]

Answer:

The rate constant at T = 100 C is 1.0*10⁻³

Explanation:

The Arrhenius equation relates two rate constants K1 and K2 measured at temperatures T1 and T2 as shown below:

ln\frac{K_{2}}{K_{1}}=\frac{\Delta H^{0}rxn}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})

here, ΔHrxn = standard enthalpy change of the reaction

R = gas constant

From the given information:

K1 = 7.4*10^-4

T1 = 25 C = 25+273 = 298 K

T2 = 100 C = 100+273 = 373K

ΔH°=4.1kJ/mol

ln\frac{K_{2}}{7.4*10^{-4}}=\frac{4.1 kJ/mol}{0.08314kJ/mol.K}(\frac{1}{298}-\frac{1}{373})K

K2 = 1.03*10⁻³

6 0
3 years ago
The balmer series is a group of spectral lines resulting from the decay of an excited electron in a hydrogen atom to what atomic
mel-nik [20]

Every line in the hydrogen spectrum that was in the visible light area had a relationship to a single number, which caught Balmer's attention. Its numeric value was 364.50682 nm. Any number more than 2 may be squared, divided by itself squared minus 4, and then multiplied by 364.50682 to obtain the wavelength of another line in the hydrogen spectrum (see the equation below). His formula predicted lines that were later discovered but had not yet been detected, allowing him to demonstrate that certain measurements of lines performed in his era using spectroscopy were somewhat off. He also turned out to be the series' capstone in terms of number.

The Balmer equation was first stated as follows (apart from a notation adjustment to provide Balmer's constant as B), and it could be used to determine the wavelength of the absorption/emission lines:

$\lambda=B\left(\frac{n^{2}}{n^{2}-m^{2}}\right)=B\left(\frac{n^{2}}{n^{2}-2^{2}}\right)$

Where

$\lambda$ is the wavelength.

B is a constant with the value of 3.6450682 \times 10^{-7} \mathrm{~m}$ or $364.50682 \mathrm{~nm}$.

m is equal to 2

n is an integer such that $n > m$.

What is the atomic energy level?

  • The set distances from an atom's nucleus where electrons may be found are referred to as energy levels (also known as electron shells).
  • In an atom, the small, positively charged nucleus is surrounded by smaller, negatively charged electrons.
  • Energy levels resemble the rungs of a ladder in several ways.

So the more about atomic energy level visit.

brainly.com/question/3930010

#SPJ4

4 0
2 years ago
How much carbon dioxide in kilograms is produced upon the complete combustion of 29.4 L of propane (approximate contents of one
Novosadov [1.4K]

Answer:

61kg

Explanation:

Like all other hydrocarbons, the combustion of propane will yield water and carbon iv oxide.

Let’s write a complete and balanced chemical equation for this.

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)

Now, we first convert the information into a mass.

We know that mass = density * volume

Let’s convert the volume here into ml since density is in mL. It must be remembered that 1000ml = 1L. Hence, 29.4L = 29,400ml

The mass is thus = 0.6921 * 29,400 = 20,347.74g

Now from the balanced equation, we can see that one mole of propane produced 3 moles of carbon iv oxide. This is the theoretical relation.

Let’s now calculate the actual number of moles. The number of moles of propane produced is the mass of propane divided by the molar mass of propane. The molar mass of propane is 3(12) + 8(1) = 36 + 8 = 44g/mol

The number of moles = 20,347.74/44 = 462.44

We simply multiply this number by 3 to get the actual number of moles of carbon dioxide produced. This is equals 1387.35 moles

Since we know this, we now calculate the mass of carbon iv oxide produced. The mass is equals the number of moles multiplied by the molar mass. The molar mass of carbon iv oxide is 44g/mol.

The mass produced is thus 1387.35 * 44 = 61,043g

To get the kilogram equivalent, we simply divide by 1000 = 61,043/1000 = 61kg

6 0
3 years ago
Express in scientific notation 0.00000000000013 =
vovangra [49]
1.3 x 10 to the power of 13 if I am not mistaken.
7 0
3 years ago
Read 2 more answers
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