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Juliette [100K]
3 years ago
13

Your pharmacy stocks solution 'Q' in an 8oz concentrated bottle. Solution 'Q' is usually ordered in 8%. Consequently, your stock

bottles are diluted with 16oz of distilled water to prepare 24oz of 8% solution 'Q' in a 1L glass beaker. What is the concentration of the stock bottle?
Chemistry
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

24%

Explanation:

Given that :

a pharmacy stocks solution 'Q' in an 8oz concentrated bottle

Let the solution Q be = V

so (8oz × V%)  ------   Equation 1

Consequently, the stock bottles are diluted with 16oz of distilled water to prepare 24oz of 8% solution 'Q' in a 1L glass beaker.

that means since 16oz is added to the previous concentration of 8oz which gives 24oz in 8% solution Q; we have

(24oz × 8%) ------ Equation 2

Equation equation 1 and 2 together; we have:

(8oz × V) = (24oz × 8%)

V = \frac {24 oz*8}{8 oz}

V = 3 × 8%

V = 24%

∴ the concentration of the stock bottle = 24%

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