Question

Your pharmacy stocks solution 'Q' in an 8oz concentrated bottle. Solution 'Q' is usually ordered in 8%. Consequently, your stock bottles are diluted with 16oz of distilled water to prepare 24oz of 8% solution 'Q' in a 1L glass beaker. What is the concentration of the stock bottle?

Answer 1

Answer:

24%

Explanation:

Given that :

a pharmacy stocks solution 'Q' in an 8oz concentrated bottle

Let the solution Q be = V

so (8oz × V%)  ------   Equation 1

Consequently, the stock bottles are diluted with 16oz of distilled water to prepare 24oz of 8% solution 'Q' in a 1L glass beaker.

that means since 16oz is added to the previous concentration of 8oz which gives 24oz in 8% solution Q; we have

(24oz × 8%) ------ Equation 2

Equation equation 1 and 2 together; we have:

(8oz × V) = (24oz × 8%)

V = $\frac {24 oz*8}{8 oz}$

V = 3 × 8%

V = 24%

∴ the concentration of the stock bottle = 24%