18 POINTS I'LL DO BRAINLIEST Which is the best reason for not using a moving car as a reference point?

Metallic elements can be recovered from ores that are oxides, carbonates, halides, or sulfides. Give an example of each type.

vredina [299]

Metallic elements which can be recovered from ores that are oxides, carbonates, halides, or sulfides are iron, zinc, silver and lead respectively.

Ores which is deposited in earth's crust which contain minerals and metals. Metals can be obtained economically and sold commercially.

<h3>How metals obtained from sulphide or carbonate ore? </h3>

As we get to know that it is easy to obtain metals from their oxides. So, firstly ores which is found in the form of carbonates and sulphide are converted into their oxides by using the process of calcination and roasting.

The metals which is in the middle of the activity series are moderately reactive. These metals are found in the crust of the earth is mainly found as oxides, sulphides, or carbonates.

A metal which can occur in the form of sulphide ore is lead.

A metal which can occur in the form of oxide ore is iron.

A metal which can occur in the form of carbonate ore is zinc.

A metal which can occur in the form of halides ore is silver.

Thus, we concluded that the metallic elements which can be recovered from ores that are oxides, carbonates, halides, or sulfides are iron, zinc, silver and lead respectively.

learn more about ore:

brainly.com/question/10306443

#SPJ4

6 0

1 year ago

What happens when water’s salinity increases?

bonufazy [111]

When waters salinity increases it’s freezing point will decrease. This is one of the reasons why people salt the roads after a snow storm.

8 0

2 years ago

Read 2 more answers

Which of the following has a mass of 10.0 g?

Serjik [45]

Answer:

a. 0.119mol Kr

Explanation:

To solve this problem, we must understand that;

Mass = number of moles x molar mass

Molar mass of Kr = 83.3g/mol

Ar = 40g/mol

He = 4g/mol

Ne = 20.18g/mol

a0.119 mol Kr mass = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar mass = 0.4 x 40 = 16g

C 1.25 mol He mass = 1.25 x 4 = 5g

d 2.02 mol Ne mass = 2.02 x 20.18 = 40.8

Krypton is the answer

5 0

2 years ago

What term represents a compound

alukav5142 [94]

Compound can be described using element symbol and numbers . it is a mixture which is result of two or more chemical element in such a way that atoms of different elements held together by chemical compound that are difficult to break . Most often a compound looks and behave like an element
for example :- Hydrogen and oxygen .. both of these elements are gaseous at room temperature and atmospheric pressure , but when both combined they both form compound water . ( H2O )

6 0

3 years ago

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

grin007 [14]

Answer:

$n_{C2H_5OH}^{eq}=14.234mol$

Explanation:

Hello,

In this case, the reaction is:

$C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH$

Thus, the law of mass action turns out:

$Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}$

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change $x$ result:

$[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol$

In such a way, the equilibrium constant is then:

$Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31$

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

$Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}} =20.31$

Thus, the second change, $x_2$ finally result (solving by solver or quadratic equation):

$x_2=1.234mol$

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

$n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol$

Best regards.

5 0

3 years ago