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Nana76 [90]
3 years ago
13

What is one way kinetic energy might be involved in rescue team missions ?

Physics
2 answers:
coldgirl [10]3 years ago
3 0

ANSWER: Kinetic Energy is the energy of mass in motion. In a rescue mission, kinetic energy is the most used energy to carry out the rescue operation successfully. The energy of the people involved in the rescue mission is a form of kinetic energy. The machineries involved in the rescue mission like helicopters, submarines, lifeboats are all examples of kinetic energy. To sum up, anything that moves and has a role in rescuing the victims can be termed as the kinetic energy involved in rescue team missions.

MrRa [10]3 years ago
3 0

Remember that kinetic energy is something in motion. So maybe one example is the energy in lights or a helicopter, or even people walking around or moving quickly to save others. Think of the boys trapped in the cave in Thailand they were swimming to get out. Hope this helps you!! :)

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atroni [7]

Answer:

Balances and Scales

A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance. The standard unit of measure for mass is based on the metric system and is typically denoted as kilograms or grams.

3 0
3 years ago
What current flows when a 35 v potential difference is imposed across a 1.4 kω resistor?
svetlana [45]

Current  =  (voltage) / (resistance)

              =    (35 volts) / (1,400 ohms)

              =         25 milliamperes 
5 0
3 years ago
A 1.50 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
Tema [17]

Answer:

α = 1.114 × 10⁻³ (°C)⁻¹

Explanation:

Given that:

Length of rod (L) = 1.5 m,

Diameter (d) = 0.55 cm,

Area (A) = \pi r^2

Radius (r) = d / 2 = 0.275 cm,

Voltage across the rod (V) = 15.0 V.

At initial temperature (T₀) = 20°C, the current (I₀) = 18.8 A while at a temperature (T) = 92⁰C, the current (I) = 17.4 A

a) The resistance of the rod (R) is given as:

R=\frac{Voltage(V)}{I_0} \\R=\frac{15}{18.8}=0.798\Omega

Therefore the resistivity and for the material of the rod at 20 °C (ρ) is:

\rho=\frac{RA}{L}=\frac{0.798*\pi *0.275^2}{1.5}=0.126\Omega m  

b) The temperature coefficient of resistivity at 20°C for the material of the rod (α) can be gotten from the equation:

R_T=R_0[1-\alpha (T-T_0)]\\but,R_T=\frac{V}{I}=\frac{15}{17.4}=0.862\\

Rearranging to make α the subject of formula:

\frac{R_T}{R_0} =1+\alpha (T-T_0)\\\alpha (T-T_0)=\frac{R_T}{R_0}-1\\\alpha =\frac{\frac{R_T}{R_0}-1}{(T-T_0)} \\Substituting:\\\alpha =\frac{\frac{0.862}{0.798}-1 }{92-20} \\\alpha =\frac{0.0802}{72} =1.114*10^-3(^0C)^{-1

8 0
3 years ago
Think back to coulomb's law. two coins with identical charges are placed on a lab table 1.35 m apart.
ziro4ka [17]

The Coulomb’s law is expressed mathematically as:

F = k * q1 * q2 / d^2

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F = force of attraction between 2 particles = 2.0 N

<span> k = Coulomb’s constant = 8.988 * 10^9 N m^2 / C^2</span>

q = charge of the particle

d = distance between the 2 particles = 1.35 m

 

Since the two coins have identical charges therefore q1 = q2 =q

F = k* q^2 / d^2

2.0 N = (8.988 * 10^9 N m^2 / C^2) * q^2 / (1.35 m)^2

q = 2.01 * 10^-5 C

<span>Therefore each coins have charges equivalent to 2.01 * 10^-5 C.</span>

4 0
4 years ago
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