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Taya2010 [7]
3 years ago
6

An example of a measure of the mass of an object would be

Physics
1 answer:
atroni [7]3 years ago
3 0

Answer:

Balances and Scales

A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance. The standard unit of measure for mass is based on the metric system and is typically denoted as kilograms or grams.

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Un objeto se mueve con una rapidez constante de 8 m/s. Esto significa que el objeto: a) Aumenta su rapidez en 8m/s cada segundo
Hatshy [7]

Explanation:

Constant speed means that the object is covering equal distance in equal interval of time. The motion is called uniform motion for such case. In this problem, it is given that an object is moving with a constant speed of 8 m/s. It means that it does not change its speed. It is moving with a single speed constantly.

We can say that it moves 8 meters every second or 800 cm every second.

4 0
3 years ago
What is the formula of finding displacement​
xenn [34]
Displacement is the final position of the object minus the initial position of the object.
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8 0
3 years ago
A floating boat has a weight of 100 N. What is the buoyant force on the boat?
lara31 [8.8K]
If the boat is floating, then it's just sitting there, and not accelerating
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So if its weight (acting downward) is 100 newtons, then the buoyant
force on it (acting upward) must also be 100 newtons.
4 0
3 years ago
A propeller is modeled as five identical uniform rods extending radially from its axis. The length and mass of each rod are 0.77
Vikki [24]
The formula for the rotational kinetic energy is

KE_{rot} = \frac{1}{2}(number \ of\ propellers)( I)( omega)^{2}

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ω = 573 rev/min * (2π rad/rev) * (1 min/60 s) = 60 rad/s

Then,

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6 0
3 years ago
What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s
mars1129 [50]

Answer:

\mu = \frac{1}{2tan\theta}

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

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\mu N_1 = N_2

by vertical force balance we have

N_1 = mg

now by torque balance about contact point on ground we will have

mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)

so we will have

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now from first equation we have

\mu (mg) = \frac{mg}{2tan\theta}

\mu = \frac{1}{2tan\theta}

3 0
3 years ago
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