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Taya2010 [7]
3 years ago
6

An example of a measure of the mass of an object would be

Physics
1 answer:
atroni [7]3 years ago
3 0

Answer:

Balances and Scales

A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance. The standard unit of measure for mass is based on the metric system and is typically denoted as kilograms or grams.

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A ball is thrown vertically upward from the edge of a bridge 22.0 m high with an initial speed of 16.0 m/s. The ball falls all t
KonstantinChe [14]

To solve this problem we will apply the concepts related to the kinematic equations of motion. We will start calculating the maximum height with the given speed, and once the total height of fall is obtained, we will proceed to calculate with the same formula and the new height, the speed of fall.

The expression to find the change in velocity and the height is,

v_f^2-v_0^2 = -2gh

Replacing,

0^2-16^2 = -2(9.8)h

h = 13.0612m

Thus the total height reached by the ball is

H = 22m+13.0612m

H = 35.0612m

Now calculate the velocity while dropping down from the maximum height as follows

v_f^2-v_0^2 = 2gh

Substituting the new height,

v_f^2 - 0^2 = 2(9.8)(35.0612)

v = \sqrt{687.2}

v = 26.2145m/s

3 0
3 years ago
A 62-kg person jumps from a window to a fire net 20.0 m directly below, which stretches the net 1.4 m. Assume that the net behav
gayaneshka [121]

Answer:

a) x = 0.098

b) x = 2.72 m

Explanation:

(a) To find the stretch of the fire net when the same person is lying in it, you can assume that the net is like a spring with constant spring k. It is necessary to find k.

When the person is falling down he acquires a kinetic energy K, this energy is equal to the elastic potential energy of the net when it is max stretched.

Then, you have:

K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2        (1)

m: mass of the person = 62kg

k: spring constant = ?

v: velocity of the person just when he touches the fire net = ?

x: elongation of the fire net = 1.4 m

Before the calculation of the spring constant, you calculate the final velocity of the person by using the following formula:

v^2=v_o^2+2gy

vo: initial velocity = 0 m/s

g: gravitational acceleration = 9.8 m/s^2

y: height from the person jumps = 20.0m

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(20.0m)}=14\frac{m}{s}

With this value you can find the spring constant k from the equation (1):

mv^2=kx^2\\\\k=\frac{mv^2}{x^2}=\frac{(62kg)(14m/s)^2}{(1.4m)^2}=6200\frac{N}{m}

When the person is lying on the fire net the weight of the person is equal to the elastic force of the fire net:

W=F_e\\\\mg=kx

you solve the last expression for x:

x=\frac{mg}{k}=\frac{(62kg)(9.8m/s^2)}{6200N/m}=0.098m

When the person is lying on the fire net the elongation of the fire net is 0.098m

b) To find how much would the net stretch, If the person jumps from 38 m, you first calculate the final velocity of the person again:

v=\sqrt{2gy}=\sqrt{2(9.8m/s^2)(38m)}=27.29\frac{m}{s}

Next, you calculate x from the equation (1):

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(62kg)(27.29m/s)^2}{6200N/m}}\\\\x=2.72m

The net fire is stretched 2.72 m

5 0
3 years ago
Organism would make the best index fossil. Answers a , b , c , d please help
aivan3 [116]

Answer: You didn't put what a, b, c, or d is so how is anyone supposed to know what the answer is?

5 0
3 years ago
Read 2 more answers
In which condition the acceleration of a moving vehicle become zero​
Alekssandra [29.7K]

Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

4 0
3 years ago
A sprinter starts from rest and runs with constant acceleration to a top speed of 12m/s in 4.0 seconds.
bagirrra123 [75]

Answer:

  a =  3,0 m/s²

Explanation:

En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.

          v= v₀ + a t

como el corredor parte del reposo si velocidad inicial es cero

           v =  at

           a = v/t

calculemos

          a = 12 /4,0

          a =  3,0 m/s²

4 0
3 years ago
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