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2 years ago

An example of a measure of the mass of an object would be

Physics

1 answer:

atroni [7]2 years ago

3 0

Answer:

Balances and Scales

A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance. The standard unit of measure for mass is based on the metric system and is typically denoted as kilograms or grams.

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"4. Two long, parallel wires each carry the same current I in the same direction (Fig. OQ 30.4) . Is the total magnetic field at

Nastasia [14]

Total magnetic field at the point P midway between the wires is Zero.

The higher wire's contribution to the magnetic field at point P is directed into the page, whereas the lower wire's contribution is directed out of the page. These two oppositely directed contributions to the magnetic field have identical magnitudes and cancel each other out since point P is equally spaced from the two wires and the currents flowing through them are of equal magnitude.

<h3></h3><h3>Define magnitude?</h3>

The term "magnitude" refers to an object's greatest size and direction. Scalar and vector quantities both use magnitude as a common factor. We are aware that scalar quantities are those that have just magnitude by definition. Those quantities with both magnitude and direction are considered vector quantities. It can also be used to describe how far an object has travelled or how much an object weighs in terms of its magnitude.

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5 0

1 year ago

How much pure gold (24/24) is to be added to 15.0 grams of 14 K gold (14/24) to obtain 18 K gold (18/24)?

Arlecino [84]

Answer:

10 gram gold is added

Explanation:

given data

pure gold = (24/24)

added = 15 grams

gold = 14 K ( 14/24)

gold = 18 K ( 18/24)

to find out

How much pure gold added

solution

we know here that when we add gold to get 20 K gold or 22K

so we added here 15 gram 14 K

we consider here m is pure gold added

so by composition here

we get

15 (14K) + m ( 24 K) = ( 15 + m ) (18) ...................1

solve it and find m

m = 10

so 10 gram gold is added

8 0

2 years ago

What are the adaptions of the tundra

Mekhanik [1.2K]

Answer: Migration and hibernation

Explanation: look it up ;)

7 0

2 years ago

It's a snowy day and you're pulling a friend along a

NeX [460]

The coefficient of friction between the sled and the snow is 0.119.

To find the answer, we need to know about the friction.

<h3>How to find the coefficient of friction between the sled and the snow?</h3>

Whenever a body moves over the surface of another body, a force come into play, which acts parallel to the surface of contact and oppose the relative motion. This opposing force is called friction.
To solve the problem, we have to draw the free body diagram of the given system.
We have given with the following values,

$a=0\\\alpha =35^0\\T=75N\\m=57kg$

Here, acceleration will be equal to zero, because the velocity is given as constant.

Thus, from the diagram, we can write the balancing equations as follows,

$ma=Tcos\alpha -f\\\where\\f=kN\\\N+Tsin\alpha=mg\\Thus,\\N=mg-Tsin\alpha$

Substituting N in f and f in the equation of ma, then we get,

$ma= Tcos\alpha -k(mg-Tsin\alpha )$

Substituting values, we get the coefficient of friction as,

$0=(75*cos35)-k((57*9.8)-(75sin35))\\\\k((57*9.8)-(75sin35))=(75*cos35)\\\\515.6k=61.44\\\\k=\frac{61.44}{515.6}=0.119$

Thus, we can conclude that, the coefficient of friction between the sled and the snow is 0.119.

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6 0

11 months ago

Read 2 more answers

72) What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115

Rina8888 [55]

<u>Answer:</u> The freezing point of solution is -3.34°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of calcium nitrate follows:

$Ca(NO_3)_2(aq.)\rightarrow Ca^{2+}(aq.)+2NO_3^-(aq.)$