What current flows when a 35 v potential difference is imposed across a 1.4 kω resistor?
1 answer:
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Answer:
the frequency of this mode of vibration is 138.87 Hz
Explanation:
Given;
length of the copper wire, L = 1 m
mass per unit length of the copper wire, μ = 0.0014 kg/m
tension on the wire, T = 27 N
number of segments, n = 2
The frequency of this mode of vibration is calculated as;
Therefore, the frequency of this mode of vibration is 138.87 Hz
Answer:
108.7 V
Explanation:
Two forces are acting on the particle:
- The external force, whose work is
- The force of the electric field, whose work is equal to the change in electric potential energy of the charge:
where
q is the charge
is the potential difference
The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:
and since the charge starts from rest, , so the formula becomes
In this problem, we have
is the work done by the external force
is the charge
is the final kinetic energy
Solving the formula for , we find