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e-lub [12.9K]
3 years ago
13

Reduce the work output

Physics
1 answer:
andriy [413]3 years ago
6 0
Maybe The 3rd One Not Sure!
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<em><u>m</u></em><em><u>a</u></em><em><u>s</u></em><em><u>s</u></em><em><u>=</u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u>c</u></em><em><u>e</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em>

<em><u>(</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u>÷</u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em>

<h2><em><u>b</u></em><em><u>e</u></em><em><u>c</u></em><em><u>a</u></em><em><u>u</u></em><em><u>s</u></em><em><u>e</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>o</u></em><em><u>n</u></em><em><u>'</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>a</u></em><em><u>v</u></em><em><u>e</u></em><em><u> </u></em><em><u>a</u></em><em><u>c</u></em><em><u>c</u></em><em><u>e</u></em><em><u>l</u></em><em><u>e</u></em><em><u>r</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>w</u></em><em><u>h</u></em><em><u>i</u></em><em><u>c</u></em><em><u>h</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u>n</u></em><em><u> </u></em><em><u>a</u></em><em><u>s</u></em><em><u> </u></em><em><u>m</u></em><em><u>/</u></em><em><u>s</u></em><em><u>2</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u>s</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>m</u></em><em><u>e</u></em><em><u>t</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>p</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u>s</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>.</u></em><em><u> </u></em><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>pls</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>l</u></em><em><u>l</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>n</u></em><em><u>k</u></em><em><u> </u></em><em><u>y</u></em><em><u>o</u></em><em><u>u</u></em></h2>
5 0
3 years ago
Helppppppl!!!!!!!!!!!​
RUDIKE [14]

Answer:

I think deposition of C is the oldest deposit

8 0
3 years ago
You measure its length as it passes. by how many millimeters do you determine the rod has contracted?
LUCKY_DIMON [66]
It sounds like a special relativity question but I need more info for a total answer. But remember it's length in the lab frame is
L•sqrt(1-(v/c)^2) where L is the rest length, v is its velocity magnitude and c is the speed of light. Sqrt is the square root (I'm on a phone so I can't see the math equation editor)
4 0
4 years ago
Fill in the blanks to the statement below in the next three questions: A train composed of a small engine car and a massive carg
Assoli18 [71]

Answer:

1) is equal  to, 2) is equal to, connected and moving along the same track.

Explanation:

1) The speed of the small engine car <em>is equal to</em> the speed of the massive cargo car.

2) The magnitude of the acceleration of the small engine car <em>is equal to</em> the magnitude of the acceleration of massive cargo car because they are <em>connected and moving along the same track</em>.

3 0
4 years ago
A plane flies 600 kilometers away from its bad at 400 meters per second then flies back to its base at 600 meters per second. Wh
tester [92]
Seems to me that it flies 400 m/s there and 600 m/s back the same distance.
therefore the average of 400 and 600 is 500 m/s.  The distance is the same so the normal formula of (d2-d1)/(t2-t1) is applicable.
4 0
4 years ago
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