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e-lub [12.9K]
3 years ago
13

Reduce the work output

Physics
1 answer:
andriy [413]3 years ago
6 0
Maybe The 3rd One Not Sure!
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Please Help me with any of these possible.
Fiesta28 [93]

alll factor is possible

4 0
3 years ago
Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio
leva [86]

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

5 0
3 years ago
Read 2 more answers
A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the
Paraphin [41]

1.96s and 1.86s. The time it takes to a spaceship hovering the surface of Venus to drop an object from a height of 17m is 1.96s, and the time it takes to the same spaceship hovering the surface of the Earth to drop and object from the same height is 1.86s.

In order to solve this problem, we are going to use the motion equation to calculate the time of flight of an object on Venus surface and the Earth. There is an equation of motion  that relates the height as follow:

h=v_{0} t+\frac{gt^{2}}{2}

The initial velocity of the object before the dropping is 0, so we can reduce the equation to:

h=\frac{gt^{2}}{2}

We know the height h of the spaceship hovering, and the gravity of Venus is g=8.87\frac{m}{s^{2}}. Substituting this values in the equation h=\frac{gt^{2}}{2}:

17m=\frac{8.87\frac{m}{s^{2} } t^{2}}{2}

To calculate the time it takes to an object to reach the surface of Venus dropped by a spaceship hovering from a height of 17m, we have to clear t from the equation above, resulting:

t=\sqrt{\frac{2(17m)}{8.87\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{8.87\frac{m}{s^{2} } } }=1.96s

Similarly, to calculate the time it takes to an object to reach the surface of the Earth dropped by a spaceship hovering from a height of 17m, and the gravity of the Earth g=9.81\frac{m}{s^{2}}.

t=\sqrt{\frac{2(17m)}{9.81\frac{m}{s^{2} } }} =\sqrt{\frac{34m}{9.81\frac{m}{s^{2} } } }=1.86s

8 0
3 years ago
Read 2 more answers
Olaf takes a picture of his dog using a digital camera. Which is true regarding the image of the dog detected by sensors in the
trasher [3.6K]

Answer: a. forms where light rays coming from the dog converge.

Explanation:

While photographing through digital camera, the light from the object through the lens converges and falls on image sensor.

The image breaks into many pixels and color and brightness of each pixel is measured and stored in form of number. This forms a digital image.

Thus, the correct option is a because the lens converges the light coming from the object onto the sensor.

6 0
3 years ago
Read 2 more answers
Marina walked 2km in half an hour, what was her average speed during her walk?
ad-work [718]

Answer:

4km/hr

Explanation:

6 0
3 years ago
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