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Vsevolod [243]
3 years ago
10

The barrel of a rifle has a length of 0.89 m. A bullet leaves the muzzle of a rifle with a speed of 620 m/s. What is the acceler

ation of the bullet while in the barrel? A bullet in a rifle barrel does not have constant acceleration, but constant acceleration is to be assumed for this problem.
Physics
1 answer:
guapka [62]3 years ago
6 0

Answer:

215955.06 m/s^2

Explanation:

length of barrel, s = 0.89 m

initial velocity of the bullet, u = 0 m/s

Final velocity of the bullet, v = 620 m/s

Let a be the acceleration of the bullet in the barrel

Use third equation of motion, we get

v^{2}=u^{2}+ 2as

620^{2}=0^{2}+ 2\times a \times 0.89

a = 215955.06 m/s^2

Thus, the acceleration of the bullet inside the barrel is  215955.06 m/s^2.

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1156+912 = 144v

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v = 2068/144

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Answer:

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The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

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The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

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The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

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