Question

Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =

Answer 1

V 1= 3.00 · 10^8 m/s
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5

Answer 2

Answer

The index of refraction of  medium is 1.5 .

Explanation:

Equation for  index of refraction is given by .

$n = \frac{c}{v}$

Where n is index of refraction in medium , v is speed of light in the medium and c is the speed of light in air .

As given

Light traveling through air at $3.00\times 10^8$ m/s reaches an unknown medium and slows down to $3.00\times 10^8$ m/s.

$c = 3.00\times 10^{8}$

$v = 2.00\times 10^{8}$

Putting the values in the formula

$n = \frac{3.00\times 10^{8}}{2.00\times 10^{8}}$

Solving the above

n = 1.5

Therefore the index of refraction of  medium is 1.5 .